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Operating at the same constant rate, 4 identical machines ca
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Bunuel
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Operating at the same constant rate, 4 identical machines ca [#permalink] New post  17 Oct 2017, 22:27
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Operating at the same constant rate, 4 identical machines can produce a total of 220 candles per minute. At this rate, how many candles could 10 such machines produce in 5 minutes?

(A) 512
(B) 2,200
(C) 2,750
(D) 11,000
(E) 44,000


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IlCreatore
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Re: Operating at the same constant rate, 4 identical machines ca [#permalink] New post  18 Oct 2017, 05:35
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The formula in this case is \(items = machines*time*rate\). Thus, substituting, we get the rate as \(220=4*1*x\) x = 55.

Then, we can use this rate to compute the number of candles as \(items = 10*5*55 = 2,750\).

Answer C
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JeffTargetTestPrep
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Re: Operating at the same constant rate, 4 identical machines ca [#permalink] New post  08 Jan 2018, 10:52
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Bunuel wrote:
Operating at the same constant rate, 4 identical machines can produce a total of 220 candles per minute. At this rate, how many candles could 10 such machines produce in 5 minutes?

(A) 512
(B) 2,200
(C) 2,750
(D) 11,000
(E) 44,000


We can determine the rate of 10 machines with the following proportion:

4/220 = 10/x

4x = 2200

x = 550

We know that 10 machines can produce 550 candles in one minute. Thus, in 5 minutes, 10 machines can produce 550 x 5 = 2750 candles.

Answer: C
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Re: Operating at the same constant rate, 4 identical machines ca [#permalink] New post  09 Jan 2018, 12:06
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Bunuel wrote:
Operating at the same constant rate, 4 identical machines can produce a total of 220 candles per minute. At this rate, how many candles could 10 such machines produce in 5 minutes?

(A) 512
(B) 2,200
(C) 2,750
(D) 11,000
(E) 44,000


Another approach is to take the given information and work towards the answer in steps

GIVEN: 4 machines produce 220 candles per ONE minute
So, 4 machines produce 1100 candles per FIVE minutes (a 5 times increase in time means a 5 times increase in output)
10 machines produce 2750 candles per FIVE minutes (a 2.5 times increase in machines means a 2.5 times increase in output)

Answer: C

Cheers,
Brent
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arc601
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Re: Operating at the same constant rate, 4 identical machines ca [#permalink] New post  14 Aug 2019, 17:12
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I attached how I did it.
Attachments

daum_equation_1565831837028.png
daum_equation_1565831837028.png [ 63.82 KiB | Viewed 1558 times ]

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bellavarghese
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Re: Operating at the same constant rate, 4 identical machines ca [#permalink] New post  19 Aug 2019, 10:30
thanks!
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