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One of the roots of the equation x^2 + kx - 6

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One of the roots of the equation x^2 + kx - 6 [#permalink] New post 23 Jan 2017, 09:05
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One of the roots of the equation \(x^2\)+ \(kx\) \(- 6 = 0\) is 3, and k is a constant.

Quantity A
Quantity B
The value of k
-1


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: One of the roots of the equation x^2 + kx - 6 [#permalink] New post 24 Jan 2017, 11:01
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Carcass wrote:


One of the roots of the equation \(x^2\)+ \(kx\) - 6 = 0 is 3, and k is a constant.

Quantity A
Quantity B
The value of k
-1




If 3 is a root (solution) to the equation, then x = 3 SATISFIES the equation.
In other words, we know that 3²+ k(3) - 6 = 0
Evaluate to get: 9 + 3k - 6 = 0
Simplify: 3k + 3 = 0
Subtract 3 from both sides: 3k = -3
Divide both sides by 3 to get: k = -1

So, we have:
Quantity A: -1
Quantity B: -1

Answer:
[Reveal] Spoiler:
C

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Re: One of the roots of the equation x^2 + kx - 6 [#permalink] New post 10 Nov 2018, 01:21
substitute value of x as 3 and solve for k, K= -1.
Re: One of the roots of the equation x^2 + kx - 6   [#permalink] 10 Nov 2018, 01:21
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One of the roots of the equation x^2 + kx - 6

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