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On July 1, 2017, a certain tree was 128 centimeters tall.

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On July 1, 2017, a certain tree was 128 centimeters tall. [#permalink] New post 12 Jun 2018, 04:32
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Question Stats:

66% (02:08) correct 33% (02:29) wrong based on 9 sessions
On July 1, 2017, a certain tree was 128 centimeters tall. Each year, the tree's height increases 50%.
Given this growth rate, the tree's height on July 1, 2023 will be how many centimeters greater than the tree's height on July 1, 2022?

A) (2^2)(3^4)
B) (2)(3^4)
C) (2)(3^5)
D) (4)(3^5)
E) (2)(3^6)
[Reveal] Spoiler: OA

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Brent Hanneson – Creator of greenlighttestprep.com
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1 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 1188
Followers: 44

Kudos [?]: 1059 [1] , given: 6

CAT Tests
Re: On July 1, 2017, a certain tree was 128 centimeters tall. [#permalink] New post 14 Jun 2018, 04:58
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GreenlightTestPrep wrote:
On July 1, 2017, a certain tree was 128 centimeters tall. Each year, the tree's height increases 50%.
Given this growth rate, the tree's height on July 1, 2023 will be how many centimeters greater than the tree's height on July 1, 2022?

A) (2^2)(3^4)
B) (2)(3^4)
C) (2)(3^5)
D) (4)(3^5)
E) (2)(3^6)


Let's create a growth table and look for a pattern

year | height in cm
2017: 128
2018: 128(1.5)
2019: 128(1.5)^2
2020: 128(1.5)^3
2021: 128(1.5)^4
2022: 128(1.5)^5
2023: 128(1.5)^6

The tree's height on July 1, 2023 will be how many centimeters greater than the tree's height on July 1, 2022?
Difference = 128(1.5)^6 - 128(1.5)^5
Factor out 128(1.5^5) to get: difference = 128(1.5^5)[1.5 - 1]
Simplify: difference = 128(1.5^5)[0.5]
Rewrite with fractions: difference = (2^7)(3/2)^5)(1/2)
Expand: difference = (2^7)(3^5)/(2^6)
Simplify: difference = (2)(3^5)

Answer: C

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Re: On July 1, 2017, a certain tree was 128 centimeters tall.   [#permalink] 14 Jun 2018, 04:58
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On July 1, 2017, a certain tree was 128 centimeters tall.

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