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On a certain train, children’s tickets cost $6 and adult tic

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GMAT Club Legend
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Joined: 07 Jun 2014
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GRE 1: Q167 V156
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On a certain train, children’s tickets cost $6 and adult tic [#permalink] New post 19 May 2018, 12:11
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Question Stats:

51% (01:12) correct 48% (02:18) wrong based on 29 sessions
On a certain train, tickets cost $6 each for children and $9 each for adults. The total train ticket cost for a certain group of six passengers was between $44 and $50.

Quantity A
Quantity B
The number of children in the group
The number of adults in the group


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Last edited by Carcass on 20 Jul 2018, 08:36, edited 1 time in total.
Edited by Carcass
GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1653 [0], given: 396

CAT Tests
Re: On a certain train, children’s tickets cost $6 and adult tic [#permalink] New post 28 May 2018, 13:47
Expert's post
Explanation

Even though the range of costs ($44 to $50) is fairly small, there is still more than one possibility. A good way to work this out is to start with the simplest scenario: 3 adults and 3 children. Their tickets would cost 3(9) + 3(6) = $45. That’s in the range, so it’s one possibility.

Since children’s tickets are cheaper, you don’t want to add more children to the mix (4 children, 2 adults will give you too small a total), but try switching out 1 child for 1 adult.

For 4 adults and 2 children, tickets would cost 4(9) + 2(6) = $48. Thus, Quantity A and Quantity B could be equal, or Quantity B could be greater, so the relationship cannot be determined from the information given.

Hence option D is correct!
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Sandy
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Re: On a certain train, children’s tickets cost $6 and adult tic [#permalink] New post 10 Oct 2018, 03:53
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Let the number of children = c and the number of adults = a
6*c + 9*a = (44 to 50)
c + a = 6
c = 6 - a
6*(6 - a) + 9*a = (44 to 50)
3*a = (8 to 14) then a can be 3 or 4 so there are two cases [one where a = 3 equal c = 3, while the other (a = 4) > (c = 2)]
So the correct answer is D)The relationship cannot be determined from the information given.
Re: On a certain train, children’s tickets cost $6 and adult tic   [#permalink] 10 Oct 2018, 03:53
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On a certain train, children’s tickets cost $6 and adult tic

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