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Of the following, which is the best approximation of the per

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Of the following, which is the best approximation of the per [#permalink] New post 26 Aug 2018, 03:22
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Attachment:
health.jpg
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Of the following, which is the best approximation of the percent increase in the national health expenditure per capita from 1981 to 1982 ?

(A) 35%

(B) 30%

(C) 20%

(D) 10%

(E) 5%
[Reveal] Spoiler: OA

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Re: Of the following, which is the best approximation of the per [#permalink] New post 26 Aug 2018, 06:43
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From the per capita graph in 1981 the amount is approximately 380 and in 1982 the amount was approximately 420.
% increase = \(\frac{420-380}{420} * 100\) = 9.5% which is approximately 10%
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Re: Of the following, which is the best approximation of the per [#permalink] New post 21 Feb 2019, 21:05
amorphous wrote:
From the per capita graph in 1981 the amount is approximately 380 and in 1982 the amount was approximately 420.
% increase = \(\frac{420-380}{420} * 100\) = 9.5% which is approximately 10%

we should divide by 420 or 380.
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Re: Of the following, which is the best approximation of the per [#permalink] New post 28 Feb 2019, 21:29
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AE wrote:
amorphous wrote:
From the per capita graph in 1981 the amount is approximately 380 and in 1982 the amount was approximately 420.
% increase = \(\frac{420-380}{420} * 100\) = 9.5% which is approximately 10%

we should divide by 420 or 380.


We divide by 420, the original number.

If you think about it, 420 - 380 = 40, and that's the actual increase that occured.

So we're left with \(\frac{40}{420}\), which tells us what fraction of the original number, 420, the increase, 40, is. So \(\frac{40}{420}\) is approximately equal to \(\frac{9.5}{100}\), or 9.5%. So, the increase of 40 is equal to an increase of 9.5% of our original number.
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Re: Of the following, which is the best approximation of the per [#permalink] New post 17 Jul 2020, 01:17
MagooshStudentHelp wrote:
AE wrote:
amorphous wrote:
From the per capita graph in 1981 the amount is approximately 380 and in 1982 the amount was approximately 420.
% increase = \(\frac{420-380}{420} * 100\) = 9.5% which is approximately 10%

we should divide by 420 or 380.


We divide by 420, the original number.

If you think about it, 420 - 380 = 40, and that's the actual increase that occured.

So we're left with \(\frac{40}{420}\), which tells us what fraction of the original number, 420, the increase, 40, is. So \(\frac{40}{420}\) is approximately equal to \(\frac{9.5}{100}\), or 9.5%. So, the increase of 40 is equal to an increase of 9.5% of our original number.



But isn't the original amount - the one that was in 1981 is 380?
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Re: Of the following, which is the best approximation of the per [#permalink] New post 28 Aug 2020, 12:46
Carcass wrote:
Attachment:
health.jpg


Of the following, which is the best approximation of the percent increase in the national health expenditure per capita from 1981 to 1982 ?

(A) 35%

(B) 30%

(C) 20%

(D) 10%

(E) 5%


how can you accurately estimate the values on the graph? i got the question wrong because I estimated the amounts to be 390 and 410, which threw off my percent increase calculation.
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Re: Of the following, which is the best approximation of the per [#permalink] New post 28 Aug 2020, 13:05
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You esteimate thanks your eyeball

Attachment:
screenshot.40.png
screenshot.40.png [ 39.44 KiB | Viewed 332 times ]


Attachment:
screenshot.41.png
screenshot.41.png [ 10.15 KiB | Viewed 331 times ]


As you can see the lower value is 380 and the upper 410 \(\approx\)
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Re: Of the following, which is the best approximation of the per [#permalink] New post 15 Sep 2020, 17:13
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Percentage increase is ( final - initial ) / ( initial ) . here initial is 380 and denominator should be 380. you would get approx. 10.5 %
Re: Of the following, which is the best approximation of the per   [#permalink] 15 Sep 2020, 17:13
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