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# Of 30 theater tickets sold, 20 tickets were sold at prices b

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Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink]  23 Feb 2017, 09:10
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Question Stats:

72% (00:46) correct 27% (00:23) wrong based on 126 sessions

Of 30 theater tickets sold, 20 tickets were sold at prices between $10 and$30 each and 10 tickets were sold at prices between $40 and$60 each.

 Quantity A Quantity B The average (arithmetic mean) of the prices of the 30 tickets $50 A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given. [Reveal] Spoiler: OA _________________ Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Retired Moderator Joined: 07 Jun 2014 Posts: 4808 GRE 1: Q167 V156 WE: Business Development (Energy and Utilities) Followers: 153 Kudos [?]: 2450 [3] , given: 394 Re: Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink] 28 Feb 2017, 16:06 3 This post received KUDOS Expert's post Explanation Here we have two types of tickets Type A: 20 tickets @$10 to $30 Type B: 10 tickets @$40 to $60 Now for the average of tickets to be maximum the tickets need to be sold at the highest possible price. For type A it is$30 and type B is $60. Average price of tickets = $$\frac{20 \times 30 + 10 \times 60}{20 +10}= 40$$. Hence Quantity B is greater. If we select the lower most prices the average price of tickets = $$\frac{20 \times 10 + 10 \times 40}{20 +10}= 20$$. Quantity B is still greater (as expected). Hence option B is correct. _________________ Sandy If you found this post useful, please let me know by pressing the Kudos Button Try our free Online GRE Test Director Joined: 09 Nov 2018 Posts: 507 Followers: 0 Kudos [?]: 50 [0], given: 1 Re: Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink] 14 Nov 2018, 10:15 sandy wrote: Explanation Here we have two types of tickets Type A: 20 tickets @$10 to $30 Type B: 10 tickets @$40 to $60 Now for the average of tickets to be maximum the tickets need to be sold at the highest possible price. For type A it is$30 and type B is $60. Average price of tickets = $$\frac{20 \times 30 + 10 \times 60}{20 +10}= 40$$. Hence Quantity B is greater. If we select the lower most prices the average price of tickets = $$\frac{20 \times 10 + 10 \times 40}{20 +10}= 20$$. Quantity B is still greater (as expected). Hence option B is correct. Is it necessary to check for lower range? Founder Joined: 18 Apr 2015 Posts: 9651 Followers: 199 Kudos [?]: 2366 [0], given: 9155 Re: Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink] 14 Nov 2018, 11:50 Expert's post As I can see, sandy did. _________________ Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Retired Moderator Joined: 07 Jun 2014 Posts: 4808 GRE 1: Q167 V156 WE: Business Development (Energy and Utilities) Followers: 153 Kudos [?]: 2450 [3] , given: 394 Re: Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink] 14 Nov 2018, 13:04 3 This post received KUDOS Expert's post AE wrote: Is it necessary to check for lower range? Not necessary in this case but its a good practice if you are fast enough. It's, what we call, a sanity check. On the test you might commit silly calculation errors, this is a good way to mitigate it. Also a good practice while in non test situations. _________________ Sandy If you found this post useful, please let me know by pressing the Kudos Button Try our free Online GRE Test Manager Joined: 22 Feb 2018 Posts: 163 Followers: 2 Kudos [?]: 129 [1] , given: 22 Re: Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink] 13 Dec 2018, 11:46 1 This post received KUDOS Answer: B 30 sold tickets 20 of them: priced between 10$ and 30$each 10 of them: priced between 40$ and 60$each A: The average of prices of the 30 tickets, We don’t have any accurate data about the exact price of the tickets, the only thing we know is their prices ranges. But we can construe their min and max possible values: 20 of them: priced between 10$ and 30$each For having the max: at least one ticket is cost 10$ and the others 30$10 of them: priced between 40$ and 60$each For having the max: at least one ticket is cost 40$ and the others 60$But in this case will the average of the ticket prices be 50 or more? We assumed having 9 tickets with 60$, 1 with 40$, 19 with 30$ and 1 with 10$to have the maximum possible average: But it is obvious that their mean is less than 50$ because +10$in 60$ tickets will compensate for just some of the lower prices than 50, and the others will be still less than 50$So the mean is less than 50$ and B is bigger than A.
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Re: Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink]  18 Mar 2019, 09:38
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Expert's post
Carcass wrote:

Of 30 theater tickets sold, 20 tickets were sold at prices between $10 and$30 each and 10 tickets were sold at prices between $40 and$60 each.

 Quantity A Quantity B The average (arithmetic mean) of the prices of the 30 tickets $50 A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given. Let's examine the EXTREME CASES Case i: the MINIMUM possible average price of the 30 tickets To MINIMIZE the average price, we'll consider: 20 tickets sold at$10 each, and 10 tickets sold at $40 each Cost of all 30 tickets = (20 x$10) + (10 x $40) =$200 + $400 =$600
So, average price of the 30 tickets = $600/30 =$20
We get:
QUANTITY A: $20 QUANTITY B:$50
In this case, Quantity B is greater

Case ii: the MAXIMUM possible average price of the 30 tickets
To MAXIMIZE the average price, we'll consider:
20 tickets sold at $30 each, and 10 tickets sold at$60 each
Cost of all 30 tickets = (20 x $30) + (10 x$60) = $600 +$600 = $1200 So, average price of the 30 tickets =$1200/30 = $40 We get: QUANTITY A:$40
QUANTITY B: $50 In this case, Quantity B is greater Since we've examined the two EXTREME cases, we can be certain that Quantity B is greater Answer: B RELATED VIDEO FROM MY COURSE _________________ Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Day emails Manager Joined: 22 Feb 2018 Posts: 163 Followers: 2 Kudos [?]: 129 [1] , given: 22 Re: Of 30 theater tickets sold, 20 tickets were sold at prices b [#permalink] 22 Mar 2019, 01:13 1 This post received KUDOS Answer: B Total number of tickets: 30 Between 10 and 30$: 20
Between 40 and 60\$: 10

The most possible value would be if 19 out of 20 were sold by 30 and 1 by 10 dollars.
And for the other 10, 9 in price 60 and 1 in price 40.
Just create a sequence like :
10, 30,30,30,..,30, 40, 60, 60, …, 60
There are 9 ones in 60 which are 10 more than B (50) and they will never compensate that 19 tickets with price 30 (each 20 less than 50) or the two others (40,10). So the average is definitely less than 50 even in the maximum case.
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Re: Of 30 theater tickets sold, 20 tickets were sold at prices b   [#permalink] 22 Mar 2019, 01:13
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