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O is the center of the circle, and [#permalink]
Expert's post 00:00

Question Stats: 66% (01:32) correct 33% (01:20) wrong based on 12 sessions
Attachment: circle.jpg [ 14.32 KiB | Viewed 596 times ]

O is the center of the circle, and $$\angle ROS$$ is a right angle.

 Quantity A Quantity B $$\frac{PQ}{RS}$$ $$\frac{2}{1}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

_________________ Director Joined: 20 Apr 2016
Posts: 824
WE: Engineering (Energy and Utilities)
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Re: O is the center of the circle, and [#permalink]
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Carcass wrote:
Attachment:
circle.jpg

O is the center of the circle, and $$\angle ROS$$ is a right angle.

 Quantity A Quantity B $$\frac{PQ}{RS}$$ $$\frac{2}{1}$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

For the diagram,
PQ = diameter of the circle, as it is passing through the centre

OR = OS = Radius of the circle and $$\angle ROS$$ = 90°.

so the$$\triangle ORS$$ is a 45°-90°-45°

and the sides are divided in $$1 : 1 : \sqrt2$$

therefore $$OR = OS = 1$$ and $$RS = \sqrt 2$$

and$$PQ = 1 + 1 = 2$$

Now QTY A =$$\frac{PQ}{RS}= \frac{2}{\sqrt2} = \sqrt2 = 1.44$$

QTY B = 2

Therefore $$QTY A < QTY B.$$

OPtion B.
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Re: O is the center of the circle, and [#permalink]
Tricky Re: O is the center of the circle, and   [#permalink] 18 Jan 2019, 20:12
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