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O is the center of the circle, and

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O is the center of the circle, and [#permalink] New post 28 Jul 2018, 10:10
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Question Stats:

66% (01:32) correct 33% (01:20) wrong based on 12 sessions
Attachment:
circle.jpg
circle.jpg [ 14.32 KiB | Viewed 596 times ]


O is the center of the circle, and \(\angle ROS\) is a right angle.

Quantity A
Quantity B
\(\frac{PQ}{RS}\)
\(\frac{2}{1}\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: O is the center of the circle, and [#permalink] New post 28 Jul 2018, 23:02
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Carcass wrote:
Attachment:
circle.jpg


O is the center of the circle, and \(\angle ROS\) is a right angle.

Quantity A
Quantity B
\(\frac{PQ}{RS}\)
\(\frac{2}{1}\)



A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E



For the diagram,
PQ = diameter of the circle, as it is passing through the centre

OR = OS = Radius of the circle and \(\angle ROS\) = 90°.

so the\(\triangle ORS\) is a 45°-90°-45°

and the sides are divided in \(1 : 1 : \sqrt2\)

therefore \(OR = OS = 1\) and \(RS = \sqrt 2\)

and\(PQ = 1 + 1 = 2\)


Now QTY A =\(\frac{PQ}{RS}= \frac{2}{\sqrt2} = \sqrt2 = 1.44\)

QTY B = 2

Therefore \(QTY A < QTY B.\)

OPtion B.
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Re: O is the center of the circle, and [#permalink] New post 18 Jan 2019, 20:12
Tricky
Re: O is the center of the circle, and   [#permalink] 18 Jan 2019, 20:12
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