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# n/x=428 and n/y=107

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n/x=428 and n/y=107 [#permalink]  25 Aug 2018, 08:42
Expert's post
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Question Stats:

69% (00:36) correct 30% (00:42) wrong based on 23 sessions
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

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Director
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WE: Engineering (Energy and Utilities)
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Kudos [?]: 645 [2] , given: 141

Re: n/x=428 and n/y=107 [#permalink]  25 Aug 2018, 10:06
2
KUDOS
Carcass wrote:
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

The numerator of both the quantities is n, and $$n > 0$$

so the denominator with the highest value will yield lower value.

so $$\frac{n}{428} < \frac{n}{107}$$

i.e. Option A < Option B

Hence option B is the answer
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GRE Instructor
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Kudos [?]: 1668 [1] , given: 8

Re: n/x=428 and n/y=107 [#permalink]  01 May 2019, 04:41
1
KUDOS
Expert's post
Carcass wrote:
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

Another approach:

Given:
n/x = 428
n/y = 107

Divide the bottom equation into the top equation to get: (n/x)/(n/y) = 428/107

Simplify: (n/x)(y/n) = some number greater than 1

Simplify: y/x = some number greater than 1

Since x and y are POSITIVE, we know that the numerator (y) must be greater than the denominator (x)

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

Re: n/x=428 and n/y=107   [#permalink] 01 May 2019, 04:41
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