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Founder  Joined: 18 Apr 2015
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n/x=428 and n/y=107 [#permalink]
Expert's post 00:00

Question Stats: 68% (00:31) correct 31% (00:54) wrong based on 29 sessions
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

_________________ Director Joined: 20 Apr 2016
Posts: 963
WE: Engineering (Energy and Utilities)
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Re: n/x=428 and n/y=107 [#permalink]
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Carcass wrote:
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

The numerator of both the quantities is n, and $$n > 0$$

so the denominator with the highest value will yield lower value.

so $$\frac{n}{428} < \frac{n}{107}$$

i.e. Option A < Option B

Hence option B is the answer
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Re: n/x=428 and n/y=107 [#permalink]
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Expert's post
Carcass wrote:
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

Another approach:

Given:
n/x = 428
n/y = 107

Divide the bottom equation into the top equation to get: (n/x)/(n/y) = 428/107

Simplify: (n/x)(y/n) = some number greater than 1

Simplify: y/x = some number greater than 1

Since x and y are POSITIVE, we know that the numerator (y) must be greater than the denominator (x)

Answer: B

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Day emails Re: n/x=428 and n/y=107   [#permalink] 01 May 2019, 04:41
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