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# n/x=428 and n/y=107

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Joined: 18 Apr 2015
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Kudos [?]: 1159 [0], given: 5501

n/x=428 and n/y=107 [#permalink]  25 Aug 2018, 08:42
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Question Stats:

58% (00:55) correct 41% (00:42) wrong based on 17 sessions
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

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Joined: 20 Apr 2016
Posts: 828
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 606 [2] , given: 124

Re: n/x=428 and n/y=107 [#permalink]  25 Aug 2018, 10:06
2
KUDOS
Carcass wrote:
$$\frac{n}{x}=428$$ and $$\frac{n}{y}=107$$

$$n > 0$$

 Quantity A Quantity B x y

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

The numerator of both the quantities is n, and $$n > 0$$

so the denominator with the highest value will yield lower value.

so $$\frac{n}{428} < \frac{n}{107}$$

i.e. Option A < Option B

Hence option B is the answer
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Re: n/x=428 and n/y=107   [#permalink] 25 Aug 2018, 10:06
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