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n/x=428 and n/y=107

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n/x=428 and n/y=107 [#permalink] New post 25 Aug 2018, 08:42
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Question Stats:

69% (00:36) correct 30% (00:42) wrong based on 23 sessions
\(\frac{n}{x}=428\) and \(\frac{n}{y}=107\)

\(n > 0\)

Quantity A
Quantity B
x
y


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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[Reveal] Spoiler: OA

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Re: n/x=428 and n/y=107 [#permalink] New post 25 Aug 2018, 10:06
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Carcass wrote:
\(\frac{n}{x}=428\) and \(\frac{n}{y}=107\)

\(n > 0\)

Quantity A
Quantity B
x
y


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E


The numerator of both the quantities is n, and \(n > 0\)

so the denominator with the highest value will yield lower value.

so \(\frac{n}{428} < \frac{n}{107}\)

i.e. Option A < Option B

Hence option B is the answer
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Re: n/x=428 and n/y=107 [#permalink] New post 01 May 2019, 04:41
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Expert's post
Carcass wrote:
\(\frac{n}{x}=428\) and \(\frac{n}{y}=107\)

\(n > 0\)

Quantity A
Quantity B
x
y



Another approach:

Given:
n/x = 428
n/y = 107


Divide the bottom equation into the top equation to get: (n/x)/(n/y) = 428/107

Simplify: (n/x)(y/n) = some number greater than 1

Simplify: y/x = some number greater than 1

Since x and y are POSITIVE, we know that the numerator (y) must be greater than the denominator (x)

Answer: B

Cheers,
Brent
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Re: n/x=428 and n/y=107   [#permalink] 01 May 2019, 04:41
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