IlCreatore wrote:
I interpreted the first way.
Thus,
1^^ = 1! - 1 = 0
2^^ = 2! - 4 = -2
3^^ = 3! - 9 = -3
4^^ = 4! - 16 = 18
So, I would say there are two cases in which n^^<0. Now, we have to find which one of the choice has value 2.
Given our prior computations, it is easy to notice that 1^^-2^^ = 0 - (-2) = 2.
Thus, the answer is B!
you are right, i missed it
_________________
If you found this post useful, please let me know by pressing the Kudos Button
Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html