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# n is an integer, and n^2 < 39

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n is an integer, and n^2 < 39 [#permalink]  05 Mar 2017, 08:46
Expert's post
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Question Stats:

69% (00:26) correct 30% (00:22) wrong based on 42 sessions

n is an integer, and $$n^2 < 39$$

 Quantity A Quantity B The greatest possible value of n minus the least possible value of n 12

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1614 [2] , given: 376

Re: n is an integer, and n^2 < 39 [#permalink]  11 Mar 2017, 16:59
2
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Expert's post
Explanation

We know that n is an integer.

And $$n^2 < 39$$. The largest perfect square less than 39 is 36

So $$n^2 = 36$$. Solving for n we get

$$n = +6$$ and $$-6$$.

The greatest possible value of n minus the least possible value of $$n = 6 - (-6)$$.

Hence both quantities are equal. Hence option C is correct.
_________________

Sandy
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Re: n is an integer, and n^2 < 39 [#permalink]  15 Mar 2018, 16:58
1
KUDOS
correct: C
n is an integer, so it can be either positive or negative. n^2 < 39 so - (root of 39) < n < root of 39
39 doesn't have an integer root. n can be at most 6 and at least -6.
A: 6 - (-6) = 12
So A and B are equal.
Manager
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Kudos [?]: 17 [0], given: 33

Re: n is an integer, and n^2 < 39 [#permalink]  16 Mar 2018, 03:19
Wow you've made the problem look so easy.

sandy wrote:
Explanation

We know that n is an integer.

And $$n^2 < 39$$. The largest perfect square less than 39 is 36

So $$n^2 = 36$$. Solving for n we get

$$n = +6$$ and $$-6$$.

The greatest possible value of n minus the least possible value of $$n = 6 - (-6)$$.

Hence both quantities are equal. Hence option C is correct.
Re: n is an integer, and n^2 < 39   [#permalink] 16 Mar 2018, 03:19
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