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n is an integer, and n^2 < 39

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n is an integer, and n^2 < 39 [#permalink] New post 05 Mar 2017, 08:46
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67% (00:31) correct 32% (00:46) wrong based on 65 sessions


n is an integer, and \(n^2 < 39\)

Quantity A
Quantity B
The greatest possible value of n minus the least possible value of n
12


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: n is an integer, and n^2 < 39 [#permalink] New post 11 Mar 2017, 16:59
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Explanation

We know that n is an integer.

And \(n^2 < 39\). The largest perfect square less than 39 is 36

So \(n^2 = 36\). Solving for n we get

\(n = +6\) and \(-6\).

The greatest possible value of n minus the least possible value of \(n = 6 - (-6)\).

Hence both quantities are equal. Hence option C is correct.
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Re: n is an integer, and n^2 < 39 [#permalink] New post 15 Mar 2018, 16:58
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correct: C
n is an integer, so it can be either positive or negative. n^2 < 39 so - (root of 39) < n < root of 39
39 doesn't have an integer root. n can be at most 6 and at least -6.
A: 6 - (-6) = 12
So A and B are equal.
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Re: n is an integer, and n^2 < 39 [#permalink] New post 16 Mar 2018, 03:19
Wow you've made the problem look so easy.

sandy wrote:
Explanation

We know that n is an integer.

And \(n^2 < 39\). The largest perfect square less than 39 is 36

So \(n^2 = 36\). Solving for n we get

\(n = +6\) and \(-6\).

The greatest possible value of n minus the least possible value of \(n = 6 - (-6)\).

Hence both quantities are equal. Hence option C is correct.
Re: n is an integer, and n^2 < 39   [#permalink] 16 Mar 2018, 03:19
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