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Founder  Joined: 18 Apr 2015
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Expert's post 00:00

Question Stats: 35% (00:34) correct 64% (00:32) wrong based on 159 sessions

n is an integer.

 Quantity A Quantity B $$(-1)^{2^{n+1}}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Last edited by Carcass on 03 Oct 2019, 12:32, edited 1 time in total.
Formatted
Director Joined: 03 Sep 2017
Posts: 518
Followers: 2

Kudos [?]: 432 , given: 66

Re: n is an integer. [#permalink]
Whatever is n, 2n+1 is always odd. Thus, quantity A is always -1, while quantity B is always 1 because it does not matter if the exponent is even or odd.

How can it be D? What am I losing?
Founder  Joined: 18 Apr 2015
Posts: 13352
Followers: 288

Kudos [?]: 3385 , given: 12187

Re: n is an integer. [#permalink]
Expert's post
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT $$2n + 1$$ but it is (if you notice very carefully) that 2 (in the first quantity) is $$2^{n+1}$$
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GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Director Joined: 03 Sep 2017
Posts: 518
Followers: 2

Kudos [?]: 432  , given: 66

Re: n is an integer. [#permalink]
1
KUDOS
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT $$2n + 1$$ but it is (if you notice very carefully) that 2 (in the first quantity) is $$2^{n+1}$$

Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as $$2^{n+1} = 2n+2$$. Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?
Intern Joined: 12 Nov 2017
Posts: 30
Followers: 1

Kudos [?]: 12 , given: 32

Re: n is an integer. [#permalink]
Shouldnt the answer be "B" ?
becuase A is always -1 and B is always 1
Carcass wrote:

n is an integer.

 Quantity A Quantity B $$(-1)^2^^{n+1}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Intern Joined: 12 Nov 2017
Posts: 30
Followers: 1

Kudos [?]: 12 , given: 32

Re: n is an integer. [#permalink]
Thank you now I get it
IlCreatore wrote:
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT $$2n + 1$$ but it is (if you notice very carefully) that 2 (in the first quantity) is $$2^{n+1}$$

Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as $$2^{n+1} = 2n+2$$. Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?
Intern Joined: 14 Jun 2018
Posts: 36
Followers: 0

Kudos [?]: 9 , given: 100

Re: n is an integer. [#permalink]
Carcass wrote:

n is an integer.

 Quantity A Quantity B $$(-1)^{2}^{n+1}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Carcass, you are still writing it (D)? I agree that it's (C).
Intern Joined: 15 May 2018
Posts: 38
Followers: 0

Kudos [?]: 6 , given: 1

Re: n is an integer. [#permalink]
Carcass wrote:

n is an integer.

 Quantity A Quantity B $$(-1)^{2}^{n+1}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given. Active Member  Joined: 27 Aug 2019
Posts: 59
Followers: 0

Kudos [?]: 51  , given: 41

Re: n is an integer. [#permalink]
1
KUDOS
IlCreatore wrote:
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT $$2n + 1$$ but it is (if you notice very carefully) that 2 (in the first quantity) is $$2^{n+1}$$

Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as $$2^{n+1} = 2n+2$$. Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?

You did right in considering the exponent as 2n+2. Since n is an integer, if for example you consider n=-1, then 2n+2 = 0. Then answer A would be equal to answer B. Thus you cannot get to a definite conclusion. Answer is D.

Regards
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GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Intern Joined: 13 Nov 2018
Posts: 36
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Kudos [?]: 15  , given: 0

Re: n is an integer. [#permalink]
1
KUDOS
since n is a integer. if the n =1 then the value in A is -1 while in B is 1. if the n=2 then the both values are equal. Re: n is an integer.   [#permalink] 03 Oct 2019, 12:47
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