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# n is an integer.

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Moderator
Joined: 18 Apr 2015
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n is an integer. [#permalink]  20 Oct 2017, 02:26
Expert's post
00:00

Question Stats:

28% (00:32) correct 71% (00:32) wrong based on 69 sessions

n is an integer.

 Quantity A Quantity B $$(-1)^{2}^{n+1}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________
Director
Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 343 [0], given: 66

Re: n is an integer. [#permalink]  20 Oct 2017, 07:23
Whatever is n, 2n+1 is always odd. Thus, quantity A is always -1, while quantity B is always 1 because it does not matter if the exponent is even or odd.

How can it be D? What am I losing?
Moderator
Joined: 18 Apr 2015
Posts: 5567
Followers: 89

Kudos [?]: 1117 [0], given: 5159

Re: n is an integer. [#permalink]  20 Oct 2017, 16:20
Expert's post
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT $$2n + 1$$ but it is (if you notice very carefully) that 2 (in the first quantity) is $$2^{n+1}$$
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Director
Joined: 03 Sep 2017
Posts: 521
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Kudos [?]: 343 [1] , given: 66

Re: n is an integer. [#permalink]  21 Oct 2017, 07:37
1
KUDOS
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT $$2n + 1$$ but it is (if you notice very carefully) that 2 (in the first quantity) is $$2^{n+1}$$

Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as $$2^{n+1} = 2n+2$$. Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?
Intern
Joined: 12 Nov 2017
Posts: 28
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Kudos [?]: 10 [0], given: 30

Re: n is an integer. [#permalink]  04 Mar 2018, 02:19
Shouldnt the answer be "B" ?
becuase A is always -1 and B is always 1
Carcass wrote:

n is an integer.

 Quantity A Quantity B $$(-1)^2^^{n+1}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Intern
Joined: 12 Nov 2017
Posts: 28
Followers: 1

Kudos [?]: 10 [0], given: 30

Re: n is an integer. [#permalink]  20 Mar 2018, 11:54
Thank you now I get it
IlCreatore wrote:
Carcass wrote:
Sorry, sometimes the forum does not show properly the formatting (or maybe I am wrong).

It is NOT $$2n + 1$$ but it is (if you notice very carefully) that 2 (in the first quantity) is $$2^{n+1}$$

Ok, yes the forum wasn't showing it right.

Thanks

I edit my answer then. The exponent in quantity A can be rewritten as $$2^{n+1} = 2n+2$$. Thus, the exponent is always even and -1 to an even exponent becomes 1, so the answer would be C, not D. Sorry for bothering you but may you provide the OE?
Intern
Joined: 14 Jun 2018
Posts: 36
Followers: 0

Kudos [?]: 7 [0], given: 100

Re: n is an integer. [#permalink]  09 Jul 2018, 01:50
Carcass wrote:

n is an integer.

 Quantity A Quantity B $$(-1)^{2}^{n+1}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Carcass, you are still writing it (D)? I agree that it's (C).
Intern
Joined: 15 May 2018
Posts: 39
Followers: 0

Kudos [?]: 5 [0], given: 1

Re: n is an integer. [#permalink]  09 Jul 2018, 18:32
Carcass wrote:

n is an integer.

 Quantity A Quantity B $$(-1)^{2}^{n+1}$$ $$(1)^n$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Re: n is an integer.   [#permalink] 09 Jul 2018, 18:32
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# n is an integer.

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