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Mr. Chang sold 100 oranges to customers for $300 and earned

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Mr. Chang sold 100 oranges to customers for $300 and earned [#permalink] New post 29 Apr 2019, 01:45
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Mr. Chang sold 100 oranges to customers for $300 and earned a profit.


Quantity A
Quantity B
The percentage of the profit that Chang got
The selling price of the oranges expressed as a percentage of the cost


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: Mr. Chang sold 100 oranges to customers for $300 and earned [#permalink] New post 01 May 2019, 16:30
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Let x be the profit, SP per orange= 300/100=3,CP per orange = 3-x

QTY A: x/3
QTY B: 3/(3-x)
Lets assume that profit is 1.
QTY A: 1/3
QTY B: 3/2
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Re: Mr. Chang sold 100 oranges to customers for $300 and earned [#permalink] New post 10 Aug 2019, 12:40
Can someone please explain this?
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Re: Mr. Chang sold 100 oranges to customers for $300 and earned [#permalink] New post 10 Aug 2019, 23:46
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The seller made a profit selling 100 oranges for 300 dollars.

So each orange selling price was 3 dollars.

Now, these 3 dollars are already the final price via wich the merchant made a profit. so the cost price of one orange is 3 minus some buck.

If I bought an orange at 2,80 dollars and sell it at 3 dollars my gain is 0.2 dollars. This is basic accountability.

Quantity A says the % of profit which is our 0.2 dollars of difference called as X so \(\frac{x}{3}\)

Quantity B says the selling price expressed as % of the cost price. So \(\frac{x}{3-x}\)

Now \(\frac{x}{3} = \frac{x}{3-x}\)

Clearly, B is bigger because the fraction is smaller
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Re: Mr. Chang sold 100 oranges to customers for $300 and earned   [#permalink] 10 Aug 2019, 23:46
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Mr. Chang sold 100 oranges to customers for $300 and earned

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