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# Mike, Scott, Jim, Kate, and Pete each have a different numbe

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Mike, Scott, Jim, Kate, and Pete each have a different numbe [#permalink]  29 Nov 2019, 03:15
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Question Stats:

57% (00:46) correct 42% (00:45) wrong based on 7 sessions
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

Indicate all such people.

A. Mike

B. Scott

C. Jim

D. Kate

E. Pete

Kudos for the right answer and explanation
[Reveal] Spoiler: OA

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Intern
Joined: 05 Oct 2019
Posts: 26
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Kudos [?]: 24 [1] , given: 15

Re: Mike, Scott, Jim, Kate, and Pete each have a different numbe [#permalink]  29 Nov 2019, 19:05
1
KUDOS
Could you someone explain how Jim and Pete could have the median number of assignments ?
Below was my approach:
We know from given: P<K, K>M, M>J, J>S, which implies the order
P,K,M,J,S
making Mike as the only possible person who could have the median number of assignments
--------------------------
Thanks praveensamudrala. Its my bad, I messed up the equality order. Possible of order of arrangements

P, S, J, M, K (median is J)
or

S, P, J, M, K (median is J)
or

S, J, P, M, K (median is P)
or

S, J, M, P, K (median is M)

So Mike, Jim and Pete could be medians (options A,C,E)

Last edited by luffy on 29 Nov 2019, 20:15, edited 1 time in total.
Intern
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Kudos [?]: 18 [2] , given: 0

Re: Mike, Scott, Jim, Kate, and Pete each have a different numbe [#permalink]  29 Nov 2019, 19:45
2
KUDOS
From the question, we can get an understanding that P<K, K>M, M>J, J>S. From this we can get 2 orders, P<K and S<J<M<K. So, the possible orders are:
S<J<M<P<K - median is M
S<J<P<M<K - median is P
S<P<J<M<K - median is J
P<S<J<M<K - median is J
Thus, the possible answers are Mike, Pete and Jim.
I suppose these are the correct answers, I'm new here so don't now how to check for the correct answer.
Intern
Joined: 05 Oct 2019
Posts: 26
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Kudos [?]: 24 [1] , given: 15

Re: Mike, Scott, Jim, Kate, and Pete each have a different numbe [#permalink]  29 Nov 2019, 20:16
1
KUDOS
praveensamudrala wrote:
From the question, we can get an understanding that P<K, K>M, M>J, J>S. From this we can get 2 orders, P<K and S<J<M<K. So, the possible orders are:
S<J<M<P<K - median is M
S<J<P<M<K - median is P
S<P<J<M<K - median is J
P<S<J<M<K - median is J
Thus, the possible answers are Mike, Pete and Jim.
I suppose these are the correct answers, I'm new here so don't now how to check for the correct answer.

--------------------

These are the correct answers, you may click on "Reveal" in "[Reveal] Spoiler: OA" just below the question
Re: Mike, Scott, Jim, Kate, and Pete each have a different numbe   [#permalink] 29 Nov 2019, 20:16
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