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# Mike drives 45 mph to work and arrives in 20 minutes. If he

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Senior Manager
Joined: 20 May 2014
Posts: 282
Followers: 18

Kudos [?]: 50 [0], given: 220

Mike drives 45 mph to work and arrives in 20 minutes. If he [#permalink]  02 Oct 2017, 22:28
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Question Stats:

100% (00:46) correct 0% (00:00) wrong based on 3 sessions
Mike drives 45 mph to work and arrives in 20 minutes. If he wants to complete the trip in 15 minutes, how fast must he drive?

(A) 42

(B) 50

(C) 54

(D) 57

(E) 60

Kudos for correct solution.
[Reveal] Spoiler: OA
Director
Joined: 03 Sep 2017
Posts: 521
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Kudos [?]: 343 [1] , given: 66

Re: Mike drives 45 mph to work and arrives in 20 minutes. If he [#permalink]  03 Oct 2017, 04:28
1
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Using the basic formula $$speed = \frac{distance}{time}$$, we can easily compute the distance to work as $$45*\frac{1}{3} = 15$$, where 45 is the speed and 1/3 is 20 minutes in hours.

Now, we want to compute the speed necessary to do the same trip in 15 minutes, or 1/4 hours. Thus, $$15*4 = 60$$. The speed is 60 mph.

Re: Mike drives 45 mph to work and arrives in 20 minutes. If he   [#permalink] 03 Oct 2017, 04:28
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