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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # Machine R, working alone at a constant rate, produces x unit  Question banks Downloads My Bookmarks Reviews Important topics
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TAGS: Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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Kudos [?]: 3037  , given: 394

Machine R, working alone at a constant rate, produces x unit [#permalink]
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Expert's post 00:00

Question Stats: 85% (01:07) correct 14% (01:32) wrong based on 217 sessions
Machine R, working alone at a constant rate, produces x units of a product in 30 minutes, and machine S, working alone at a constant rate,
produces x units of the product in 48 minutes, where x is a positive integer.

 Quantity A Quantity B The number of units ofthe product that machineR, working alone at itsconstant rate, producesin 3 hours The number of units ofthe product that machineS, working alone at itsconstant rate, producesin 4 hours

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Practice Questions
Question: 1
Page: 150
Difficulty: medium
[Reveal] Spoiler: OA

_________________

Sandy
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Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3037 , given: 394

Re: Machine R, working alone at a constant rate, produces x unit [#permalink]
Expert's post

Explanation

Let X is 1.

Number of units by A in 3 hours = $$\frac{180 min}{30 min}$$= 6
Number of units by B in 4 hours = $$\frac{240 min}{48 min}$$= 5

Hence, option $$A$$ is greater.
_________________

Sandy
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Re: Machine R, working alone at a constant rate, produces x unit [#permalink]
1
KUDOS
Expert's post
sandy wrote:
Machine R, working alone at a constant rate, produces x units of a product in 30 minutes, and machine S, working alone at a constant rate,
produces x units of the product in 48 minutes, where x is a positive integer.

 Quantity A Quantity B The number of units ofthe product that machineR, working alone at itsconstant rate, producesin 3 hours The number of units ofthe product that machineS, working alone at itsconstant rate, producesin 4 hours

IMPORTANT: When solving work questions, we must make sure that the values all feature the same units of measurement.
For example, if our rate is expressed as units per MINUTE, then our time should also be in MINUTES.
Conversely, if our rate is expressed as units per HOUR, then our time should also be in HOUR.

Let's go with MINUTES

---------------ASIDE---------------------
Rule: If a person can complete an entire job in k hours, then in one hour, the person can complete 1/k of the job
Example: If it takes Sue 5 hours to complete a job, then in one hour, she can complete 1/5 of the job. In other words, her work rate is 1/5 of the job per hour
-----------------------------------------

Output = (rate)(time)
We know the work times are 3 hours (aka 180 MINUTES) and 4 hours (aka 240 MINUTES)
So, let's determine the rates for each machine.

Machine R, working alone at a constant rate, produces x units of a product in 30 minutes
So, in ONE MINUTE, machine R can produce x/30 units
In other words, machine R's RATE is x/30 units PER MINUTE

Machine S, working alone, produces x units of the product in 48 minutes
So, in ONE MINUTE, machine S can produce x/48 units
In other words, machine S's RATE is x/40 units PER MINUTE

QUANTITY A: The number of units of the product that machine R, working alone at its constant rate, produces in 3 hours (aka 180 MINUTES)
Output = (rate)(time)
= (x/30 units PER MINUTE)(180 MINUTES)
= 180x/30
= 6x

QUANTITY B: The number of units of the product that machine S, working alone at its constant rate, produces in 4 hours (aka 240 MINUTES)
Output = (rate)(time)
= (x/40 units PER MINUTE)(240 MINUTES)
= 240x/48
= 5x

So, we have:
Quantity A: 6x
Quantity B: 5x

Since x is POSITIVE, we can see that Quantity A is greater.

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com  Manager Joined: 22 Feb 2018
Posts: 163
Followers: 2

Kudos [?]: 139  , given: 22

Re: Machine R, working alone at a constant rate, produces x unit [#permalink]
1
KUDOS
R: x units in 30. Minutes
S: x units in 48 minutes

A: How many products in 3 hours? / x units in 0.5 hour. Answer = 3/0.5 * x = 6x
B: How many products in 4 hours? / x units in 48/60 hour. Answer = 4 / (48/60) *x = 5x

So A is bigger than B.
(The speed of machine A is 48/30=7/5 times faster than B.)

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Senior Manager  Joined: 10 Feb 2020
Posts: 496
Followers: 2

Kudos [?]: 137 , given: 300

Re: Machine R, working alone at a constant rate, produces x unit [#permalink]
GreenlightTestPrep wrote:
sandy wrote:
Machine R, working alone at a constant rate, produces x units of a product in 30 minutes, and machine S, working alone at a constant rate,
produces x units of the product in 48 minutes, where x is a positive integer.

 Quantity A Quantity B The number of units ofthe product that machineR, working alone at itsconstant rate, producesin 3 hours The number of units ofthe product that machineS, working alone at itsconstant rate, producesin 4 hours

IMPORTANT: When solving work questions, we must make sure that the values all feature the same units of measurement.
For example, if our rate is expressed as units per MINUTE, then our time should also be in MINUTES.
Conversely, if our rate is expressed as units per HOUR, then our time should also be in HOUR.

Let's go with MINUTES

---------------ASIDE---------------------
Rule: If a person can complete an entire job in k hours, then in one hour, the person can complete 1/k of the job
Example: If it takes Sue 5 hours to complete a job, then in one hour, she can complete 1/5 of the job. In other words, her work rate is 1/5 of the job per hour
-----------------------------------------

Output = (rate)(time)
We know the work times are 3 hours (aka 180 MINUTES) and 4 hours (aka 240 MINUTES)
So, let's determine the rates for each machine.

Machine R, working alone at a constant rate, produces x units of a product in 30 minutes
So, in ONE MINUTE, machine R can produce x/30 units
In other words, machine R's RATE is x/30 units PER MINUTE

Machine S, working alone, produces x units of the product in 48 minutes
So, in ONE MINUTE, machine S can produce x/48 units
In other words, machine S's RATE is x/40 units PER MINUTE

QUANTITY A: The number of units of the product that machine R, working alone at its constant rate, produces in 3 hours (aka 180 MINUTES)
Output = (rate)(time)
= (x/30 units PER MINUTE)(180 MINUTES)
= 180x/30
= 6x

QUANTITY B: The number of units of the product that machine S, working alone at its constant rate, produces in 4 hours (aka 240 MINUTES)
Output = (rate)(time)
= (x/40 units PER MINUTE)(240 MINUTES)
= 240x/48
= 5x

So, we have:
Quantity A: 6x
Quantity B: 5x

Since x is POSITIVE, we can see that Quantity A is greater.

Cheers,
Brent

I think there is a typing mistake? It should be x/48
_________________

Ever Tried? Ever Failed? No Matter. Try Again. Fail Again. Fail Better!! Re: Machine R, working alone at a constant rate, produces x unit   [#permalink] 27 Apr 2020, 12:57
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