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M / P > N / P

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Intern
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Joined: 22 Aug 2016
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M / P > N / P [#permalink] New post 18 Feb 2017, 08:41
00:00

Question Stats:

66% (00:50) correct 33% (00:00) wrong based on 3 sessions
\(\frac{M}{P} > \frac{N}{P}\)

Quantity A
Quantity B
M
N


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Hi All,

I found this question in Manhattan book but I am not confident regarding the solution provided. This is how I solved this question.

Algebraic Solution:

Since M / P > N / P
Step 1: M / P - N/P > 0
Step 2: M - N / P > 0
Step 3: M - N > 0 (Multiplying P with 0 - doesn't matter if p is positive or negative since it is being multiplied with 0 and the end product will be 0 anyways)
Step 4: M > N

So as per my solution, Quantity A is greater than Quantity B. However, as per Manhattan, the original answer is D. Their solution is " Without knowing the signs of any of the variables, you cannot assume that m is larger. While it certainly could be (for instance, m = 4, n = 2, and p = 1), if p is negative, the reverse will be true (for instance, m = 2, n = 4, and p = -1)"

I don't know how my solution is not correct. Any comments?

I appreciate your feedback!

Regards,
H.
[Reveal] Spoiler: OA

Last edited by Carcass on 19 Feb 2017, 11:01, edited 1 time in total.
Edited by Carcass
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Re: M / P > N / P [#permalink] New post 18 Feb 2017, 09:35
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Expert's post
Hey,

Yes step 3 is wrong. Multiplying matters even if with 0


For example

-5 < 0

multiply -1 both side

If what you did in step 3 is correct.

5 < 0.

Which is well not correct.

So D is indeed the right answer.
_________________

Sandy
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Joined: 22 Aug 2016
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Kudos [?]: 9 [0], given: 5

Re: M / P > N / P [#permalink] New post 18 Feb 2017, 09:41
Got it. Thank you!
Re: M / P > N / P   [#permalink] 18 Feb 2017, 09:41
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