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m or 15

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Joined: 24 May 2016
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m or 15 [#permalink] New post 14 Mar 2018, 02:24

Question Stats:

100% (00:54) correct 0% (00:00) wrong based on 8 sessions
triangles.jpg [ 19.32 KiB | Viewed 285 times ]

Quantity A
Quantity B

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
[Reveal] Spoiler: OA

Last edited by Carcass on 14 Mar 2018, 15:23, edited 1 time in total.
Edited by Carcass
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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Re: Quantitative reasoning [#permalink] New post 14 Mar 2018, 07:22
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I am not sure if this is a GRE question. And please follow the rules of posting question.

The first triangle and the second triangle are similar. Both of them are right triangle and both the triangles have one angle equal to \(x\) degrees.

We can say that:

In triangle 1 we have hypotenuse=\(\sqrt{3^2 + 4^2}=5\) .

height of triangle 1/ height of triangle 2 = hypotenuse of triangle 1/ hypotenuse of triangle 2.

\(\frac{10}{4}=\frac{m}{5}\) so \(m=12.5\).

Hence option B is greater.

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Joined: 22 Feb 2018
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Re: m or 15 [#permalink] New post 14 Mar 2018, 15:34
Correct: B
In the left triangle, as it is a right side one, the other side is 5. And we have: cos x = 4/5
In the right triangle, angle x is equal to angle x in the left triangle. We have cos x = 10 / m = 4/5, so m is 12.5
And B is bigger than m


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Joined: 15 Feb 2018
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Re: m or 15 [#permalink] New post 16 Mar 2018, 03:54
Notice the first triangle is a 3-4-5 triangle so x = 30 degrees.

In the second triangle, we want to find the side opposite to angle x. We know that a*sqrt{3} = 10 so a = 10*sqrt{3}/3.

Now using the Pythagorean formula, m^{2} = 10^{2} + (10*sqrt{3}/3)^{2} --> m = sqrt{100 + 100/3} = 11.5 < 15. So answer is Qty B.
Re: m or 15   [#permalink] 16 Mar 2018, 03:54
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