IshanGre wrote:

IlCreatore wrote:

The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!

If possible can you please explain your solution in a bit simpler way. will be thankful.

the wording is a bit convoluted but the question is not difficult.

The question says: 3 consecutive odd integers and the least is t. The best way is to pick numbers: 5+7+9=21

Only D is the answer because M -12 = 21 -12 = 9 and our t was 9.

Hope this helps.

Regards

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