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M is the sum of three consecutive odd integers, the least o

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M is the sum of three consecutive odd integers, the least o [#permalink] New post 07 Jun 2017, 02:02
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69% (01:57) correct 30% (01:37) wrong based on 65 sessions
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Re: M is the sum of three consecutive odd integers, the least o [#permalink] New post 20 Sep 2017, 05:55
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The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!
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Re: M is the sum of three consecutive odd integers, the least o [#permalink] New post 12 May 2018, 01:55
IlCreatore wrote:
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!



If possible can you please explain your solution in a bit simpler way. will be thankful.
Founder
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Joined: 18 Apr 2015
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GRE 1: Q160 V160
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Re: M is the sum of three consecutive odd integers, the least o [#permalink] New post 12 May 2018, 09:30
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IshanGre wrote:
IlCreatore wrote:
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!



If possible can you please explain your solution in a bit simpler way. will be thankful.



the wording is a bit convoluted but the question is not difficult.

The question says: 3 consecutive odd integers and the least is t. The best way is to pick numbers: 5+7+9=21

Only D is the answer because M -12 = 21 -12 = 9 and our t was 9.

Hope this helps.

Regards
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Re: M is the sum of three consecutive odd integers, the least o [#permalink] New post 21 Nov 2018, 20:51
IshanGre wrote:
IlCreatore wrote:
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!



If possible can you please explain your solution in a bit simpler way. will be thankful.


The solution is logical. May be you are confused by a typo. Instead of (t+3), it should be (t+4) because the question is about consecutive odd. The later part is just simplification.
Re: M is the sum of three consecutive odd integers, the least o   [#permalink] 21 Nov 2018, 20:51
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