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Founder  Joined: 18 Apr 2015
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M is the sum of three consecutive odd integers, the least o [#permalink]
Expert's post 00:00

Question Stats: 66% (01:51) correct 33% (01:37) wrong based on 60 sessions

M is the sum of three consecutive odd integers, the least of which is $$t$$. In terms of M, which of the following is the sum of three consecutive odd integers, the greatest of which is t ?

A) $$M + 12$$

B) $$M + 6$$

C) $$M - 6$$

D) $$M - 12$$

E) $$\frac{M}{2}$$
[Reveal] Spoiler: OA

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GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests. Director Joined: 03 Sep 2017
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Re: M is the sum of three consecutive odd integers, the least o [#permalink]
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The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!
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Re: M is the sum of three consecutive odd integers, the least o [#permalink]
IlCreatore wrote:
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!

If possible can you please explain your solution in a bit simpler way. will be thankful.
Founder  Joined: 18 Apr 2015
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Kudos [?]: 3366 , given: 12159

Re: M is the sum of three consecutive odd integers, the least o [#permalink]
Expert's post
IshanGre wrote:
IlCreatore wrote:
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!

If possible can you please explain your solution in a bit simpler way. will be thankful.

the wording is a bit convoluted but the question is not difficult.

The question says: 3 consecutive odd integers and the least is t. The best way is to pick numbers: 5+7+9=21

Only D is the answer because M -12 = 21 -12 = 9 and our t was 9.

Hope this helps.

Regards
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Re: M is the sum of three consecutive odd integers, the least o [#permalink]
IshanGre wrote:
IlCreatore wrote:
The sum of three consecutive integers, the least being t is M = t + (t+2) + (t+3) = 3t +6. The sum of three consecutive odd integers, the largest being t is (t-4) + (t-2) + t = 3t - 6. To get the answer in terms of M, we can substitute for 3t that from the first equation is equal to M-6 obtaining that the sum becomes M-6-6 = M-12. Thus answer D!

If possible can you please explain your solution in a bit simpler way. will be thankful.

The solution is logical. May be you are confused by a typo. Instead of (t+3), it should be (t+4) because the question is about consecutive odd. The later part is just simplification. Re: M is the sum of three consecutive odd integers, the least o   [#permalink] 21 Nov 2018, 20:51
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