Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

LEARN WITH AN EXPERT TEACHER—FOR FREE - Take a free practice test, learn content with one of our highest-rated teachers, or challenge yourself with a GRE Workshop.

In this free class we’ll provide an overview of and discussion about how to maximize your score on the GRE argument essay. The first 20 minutes of this webinar will consist of a presentation and the last 40 minutes consists of live Q&A.

This admissions guide will help you plan your best route to a PhD by helping you choose the best programs your goals, secure strong letters of recommendation, strengthen your candidacy, and apply successfully.

m is a three-digit integer such that when it is divided by 5, the remainder is y, and when it is divided by 7, the remainder is also y. If y is a positive integer, what is the smallest possible value of m?

Re: m is a three-digit integer such that when it is divided by [#permalink]
12 Aug 2017, 13:44

4

This post received KUDOS

Expert's post

Carcass wrote:

m is a three-digit integer such that when it is divided by 5, the remainder is y, and when it is divided by 7, the remainder is also y. If y is a positive integer, what is the smallest possible value of m?

There's a nice rule that say, "If N divided by D equals Q with remainder R, then N = DQ + R" For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2 Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3

When m is divided by 5, the remainder is y So, m = 5k + y for some integer k

When m is divided by 7, the remainder is y So, m = 7j + y for some integer j

Since both equations are set to equal m, we can write: 5k + y = 7j + y Subtract y from both sides to get: 5k = 7j Well, 5k represents a multiple of 5, and 7j represents a multiple of 7 So, what's the smallest 3-digit number that is a multiple of 5 AND a multiple of 7?

The smallest 3-digit number is 100 100 is a multiple of 5, but it's NOT a multiple of 7

Next we have 105 105 is a multiple of 5, AND it's a multiple of 7 Now be careful. This does NOT mean that m = 105

When we divide 105 by 5 we get a remainder of 0, but we're told that the remainder (y) is a POSITIVE INTEGER. To MINIMIZE the value of m, we need a super small remainder. The smallest possible non-zero remainder is 1. 105 + 1 = 106

So, 106 is the smallest possible 3-digit value of m.

RELATED VIDEO

_________________

Brent Hanneson – Creator of greenlighttestprep.com If you enjoy my solutions, you'll like my GRE prep course. Sign up for GRE Question of the Dayemails

Re: m is a three-digit integer such that when it is divided by [#permalink]
07 Jul 2018, 12:25

1

This post received KUDOS

GreenlightTestPrep wrote:

Carcass wrote:

m is a three-digit integer such that when it is divided by 5, the remainder is y, and when it is divided by 7, the remainder is also y. If y is a positive integer, what is the smallest possible value of m?

There's a nice rule that say, "If N divided by D equals Q with remainder R, then N = DQ + R" For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2 Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3

When m is divided by 5, the remainder is y So, m = 5k + y for some integer k

When m is divided by 7, the remainder is y So, m = 7j + y for some integer j

Since both equations are set to equal m, we can write: 5k + y = 7j + y Subtract y from both sides to get: 5k = 7j Well, 5k represents a multiple of 5, and 7j represents a multiple of 7 So, what's the smallest 3-digit number that is a multiple of 5 AND a multiple of 7?

The smallest 3-digit number is 100 100 is a multiple of 5, but it's NOT a multiple of 7

Next we have 105 105 is a multiple of 5, AND it's a multiple of 7 Now be careful. This does NOT mean that m = 105

When we divide 105 by 5 we get a remainder of 0, but we're told that the remainder (y) is a POSITIVE INTEGER. To MINIMIZE the value of m, we need a super small remainder. The smallest possible non-zero remainder is 1. 105 + 1 = 106

So, 106 is the smallest possible 3-digit value of m.

RELATED VIDEO

How could i know which numbers i should use in general? What is your strategy of restricting the range of possible values for this problem?

Re: m is a three-digit integer such that when it is divided by [#permalink]
07 Jul 2018, 13:24

3

This post received KUDOS

Expert's post

This question is quite tricky.

However, 99% of the time, the more a tricky question is, the more there is always a shortcut or at a closer inspection a solution is suddenly behind the curve.

Reading carefully the stem, it says that you have to consider a 3 digit integer number and you have to find the least possible value.

So, a 3 digit number at least is 100. Now, you do also know that when it is divided by 5 y is the remainder and when it is divided by 7 is yet y the remainder, which means is the same number.

A common number that divides evenly 7 and 5 is 105. 105 divided by 5 AND 7 has no rest or reminder. From this is easy to think that a number divided by both 5 and 7 with the same reminder y, for instance, the reminder is 1, is 106.

106 is the least number with 3 digits you can have when you divide it by 5 and 7.