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m = 120 % of n

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m = 120 % of n [#permalink] New post 17 Oct 2017, 15:47
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Question Stats:

60% (00:19) correct 40% (01:22) wrong based on 10 sessions


\(m = 120 % of n\)

Quantity A
Quantity B
\(\frac{6}{5}*n\)
\(\frac{5}{6}*m\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: m = 120 % of n [#permalink] New post 18 Oct 2017, 01:02
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Quantity A is greater:

QA=m which is greater than QB=n
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Re: m = 120 % of n [#permalink] New post 18 Oct 2017, 05:08
Carcass wrote:


\(m = 120 % of n\)

Quantity A
Quantity B
\(\frac{6}{5}*n\)
\(\frac{5}{6}*m\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Is this D because of 0? I mean with every integer > 0, A is greater, while with n = 0, the two quantities are zero and thus equal. Is it right?
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Re: m = 120 % of n [#permalink] New post 18 Oct 2017, 12:30
Expert's post
This is a kind of question in which you have to do anything but observation. A closer inspection.

You can certainly manipulate the statement such as this way

\(m = \frac{6}{5} (or 120) * n\)

Substitute and you end up with \(\frac{5}{6} * \frac{6}{5} * n\). At this point you do have n.the what ?? you do not have any value for it.

Another way is looking at the stem \(m = 120% * n\) , but you do not have enough information to say N is negative or positive or a fraction along both signs.

At this point, you can stop and check D

Hope this helps.

PS: you are right after all
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Re: m = 120 % of n [#permalink] New post 06 Dec 2017, 16:32
Carcass wrote:
This is a kind of question in which you have to do anything but observation. A closer inspection.

You can certainly manipulate the statement such as this way

\(m = \frac{6}{5} (or 120) * n\)

Substitute and you end up with \(\frac{5}{6} * \frac{6}{5} * n\). At this point you do have n.the what ?? you do not have any value for it.

Another way is looking at the stem \(m = 120% * n\) , but you do not have enough information to say N is negative or positive or a fraction along both signs.

At this point, you can stop and check D

Hope this helps.

PS: you are right after all


Wrong explanation. Quantity A is Bigger. 6/5 * n can be written as m. and 5/6 m is less than that of m. Quantity A is greater.
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Re: m = 120 % of n [#permalink] New post 06 Dec 2017, 17:26
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Expert's post
Carcass wrote:


\(m = 120 % of n\)

Quantity A
Quantity B
\(\frac{6}{5}*n\)
\(\frac{5}{6}*m\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Given: m = 120 % of n
We can write: m = (120/100)n
Simplify: m = (6/5)n

Given:
Quantity A: (6/5)n
Quantity B: (5/6)m

Since we now know that m = (6/5)n, we can replace Quantity A with m to get:
Quantity A: m
Quantity B: (5/6)m

At this point, we can finish the question using matching operations

Multiply both sides by 6 to get:
Quantity A: 6m
Quantity B: 5m

Subtract 5m from both sides to get:
Quantity A: m
Quantity B: 0

If m is positive, then Quantity A is greater
If m is negative, then Quantity B is greater
If m is zero, then the quantities are equal

Answer: D


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Re: m = 120 % of n   [#permalink] 06 Dec 2017, 17:26
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