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# List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar

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Moderator
Joined: 18 Apr 2015
Posts: 5149
Followers: 77

Kudos [?]: 1030 [0], given: 4638

List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar [#permalink]  22 Nov 2017, 12:13
Expert's post
00:00

Question Stats:

100% (00:28) correct 0% (00:00) wrong based on 2 sessions
List L: 2, x, y

List M: 1, 2, 3, x, y .

If the average (arithmetic mean) of the 3 numbers in list L is $$\frac{10}{3}$$, what is the average of the 5 numbers in list M ?

[Reveal] Spoiler: OA
14/5

_________________
Moderator
Joined: 18 Apr 2015
Posts: 5149
Followers: 77

Kudos [?]: 1030 [0], given: 4638

Re: List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar [#permalink]  22 Nov 2017, 12:27
Expert's post
Explanation

List L is = to $$\frac{2+x+y}{3}=\frac{10}{3}$$. After cross multiply we do have x+y=8

List M is = to $$\frac{1+2+3+8}{5}$$ (because we do already know that x+y=8). Indeed, $$\frac{14}{5}$$
_________________
Re: List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar   [#permalink] 22 Nov 2017, 12:27
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# List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar

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