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List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar [#permalink]
22 Nov 2017, 12:13
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100% (00:28) correct
0% (00:00) wrong based on 2 sessions
List L: 2, x, y List M: 1, 2, 3, x, y . If the average (arithmetic mean) of the 3 numbers in list L is \(\frac{10}{3}\), what is the average of the 5 numbers in list M ? Give your answer as a fraction.
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Moderator
Joined: 18 Apr 2015
Posts: 5149
Followers: 77
Kudos [?]:
1030
[0], given: 4638

Re: List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar [#permalink]
22 Nov 2017, 12:27
ExplanationList L is = to \(\frac{2+x+y}{3}=\frac{10}{3}\). After cross multiply we do have x+y=8 List M is = to \(\frac{1+2+3+8}{5}\) (because we do already know that x+y=8). Indeed, \(\frac{14}{5}\)
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Re: List L: 2, x, y List M: 1, 2, 3, x, y 14. If the average (ar
[#permalink]
22 Nov 2017, 12:27





