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# Line L passes

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Line L passes [#permalink]  19 May 2017, 02:08
Expert's post
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Question Stats:

76% (00:43) correct 23% (00:26) wrong based on 39 sessions

Line l passes through $$(- \sqrt{2}, \sqrt{3} )$$ and $$( \sqrt{2}, -\sqrt{3} )$$. Line M is perpendicular to line l

 Quantity A Quantity B The slope of l The slope of M

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: Line L passes [#permalink]  09 Oct 2017, 08:22
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Given that line m is perpendicular to line l and the slope of a perpendicular line is the opposite reciprocal of the other.

Than it is enough to notice that line l slope is some negative stuff divided by some positive stuff, thus it is negative. Line m slope is then positive.

Quantity B is greater and B is the answer!
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Re: Line L passes [#permalink]  09 Oct 2017, 11:13
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Carcass wrote:

Line l passes through $$(- \sqrt{2}, \sqrt{3} )$$ and $$( \sqrt{2}, -\sqrt{3} )$$. Line M is perpendicular to line l

 Quantity A Quantity B The slope of l The slope of M

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Detailed explanation

Now we know slope of line$$m = \frac{(y2 - y1 )}{(x2 -x1)}$$

Therefore the slope of line$$l= \frac{(y2 - y1 )}{(x2 -x1)}$$ [ where y2 = $$-\sqrt{3}$$, y1 =$$\sqrt{3}$$and x2 = $$\sqrt{2}$$ and x1 =$$-\sqrt{2}$$ ]

$$=(-\sqrt{3}-\sqrt{3})/(\sqrt{2}+\sqrt{2})$$

$$= -\sqrt{3}/\sqrt{2}$$

Now slope of line $$M = \sqrt{2}/\sqrt{3}$$ (Since the slope M is perpendicular to line l and we know the slope is negative reciprocal)

Hence option B is greater since it is positive value
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Re: Line L passes [#permalink]  29 Sep 2018, 11:26
I picked B
Re: Line L passes   [#permalink] 29 Sep 2018, 11:26
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# Line L passes

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