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Line A is perpendicular to the line with the equation [#permalink]
Expert's post 00:00

Question Stats: 81% (00:52) correct 18% (01:06) wrong based on 11 sessions
Line A is perpendicular to the line with the equation $$y= - \frac{1}{5}x$$ and the point (3, -10) is on line A. Which of the following is the equation of line A?

A. $$y=- \frac{1}{5} x - \frac{47}{5}$$

B. $$y = \frac{1}{5} x -\frac{53}{5}$$

C. $$y = 5x$$

D. $$y=5x - 5$$

E. $$y=5x - 25$$
[Reveal] Spoiler: OA

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Re: Line A is perpendicular to the line with the equation [#permalink]
Carcass wrote:
Line A is perpendicular to the line with the equation $$y= - \frac{1}{5}x$$ and the point (3, -10) is on line A. Which of the following is the equation of line A?

A. $$y=- \frac{1}{5} x - \frac{47}{5}$$

B. $$y = \frac{1}{5} x -\frac{53}{5}$$

C. $$y = 5x$$

D. $$y=5x - 5$$

E. $$y=5x - 25$$

since line A is perpendicular to the line $$y= - \frac{1}{5}x$$,

so slope for line A = 5 (Since the slope of a line perpendicular to a given line is the negative inverse of the slope of the other line)

Now two points of the line a are given as (3 , -10)

Putting them in the line equation

y = mx + c

or -10 = 5 * 3 + c

or c = -25

therefore the equation of line A : y = 5x - 25
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GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests Re: Line A is perpendicular to the line with the equation   [#permalink] 03 Aug 2018, 21:25
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