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# Let x=3 , if x is an odd integer

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Let x=3 , if x is an odd integer [#permalink]  16 Aug 2019, 12:03
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Question Stats:

66% (00:46) correct 34% (00:50) wrong based on 50 sessions
Let $$\boxed {x} = 3$$ , if x is an odd integer;

Let $$\boxed {x} = 6$$, if x is an even integer.

$$r$$ and $$s$$ are integers, $$3r$$ is odd, and $$5 + s$$ is odd.

 Quantity A Quantity B $$\boxed {r}$$ $$\boxed {s}$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation
[Reveal] Spoiler: OA

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Re: Let x=3 , if x is an odd integer [#permalink]  16 Aug 2019, 14:30
Expert's post
Carcass wrote:
Let $$\boxed {x} = 3$$ , if x is an odd integer;

Let $$\boxed {x} = 6$$, if x is an even integer.

$$r$$ and $$s$$ are integers, $$3r$$ is odd, and $$5 + s$$ is odd.

 Quantity A Quantity B $$\boxed {r}$$ $$\boxed {s}$$

----ASIDE-----------------
Some important rules:
#1. ODD +/- ODD = EVEN
#2. ODD +/- EVEN = ODD
#3. EVEN +/- EVEN = EVEN

#4. (ODD)(ODD) = ODD
#5. (ODD)(EVEN) = EVEN
#6. (EVEN)(EVEN) = EVEN

-----------------------------

GIVEN:
If x is ODD, then $$\boxed {x} = 3$$
If x is EVEN, then $$\boxed {x} = 6$$

So, for example:
$$\boxed {7} = 3$$
$$\boxed {11} = 3$$
$$\boxed {3} = 3$$

And
$$\boxed {8} = 6$$
$$\boxed {22} = 6$$
$$\boxed {6} = 6$$

ALSO GIVEN:
$$3r$$ is odd
Since 3 is odd and 3r is odd, we can conclude that r is ODD
This means $$\boxed {r} = 3$$

$$5 + s$$ is odd
Since 5 is odd, we can conclude that s is EVEN
This means $$\boxed {s} = 6$$

We get:
Quantity A: 3
Quantity B: 6

Cheers,
Brent
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Re: Let x=3 , if x is an odd integer   [#permalink] 16 Aug 2019, 14:30
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