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Let x=3 , if x is an odd integer

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Let x=3 , if x is an odd integer [#permalink] New post 16 Aug 2019, 12:03
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Question Stats:

66% (00:46) correct 34% (00:50) wrong based on 50 sessions
Let \(\boxed {x} = 3\) , if x is an odd integer;

Let \(\boxed {x} = 6\), if x is an even integer.

\(r\) and \(s\) are integers, \(3r\) is odd, and \(5 + s\) is odd.

Quantity A
Quantity B
\(\boxed {r}\)
\(\boxed {s}\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation
[Reveal] Spoiler: OA

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Re: Let x=3 , if x is an odd integer [#permalink] New post 16 Aug 2019, 14:30
Expert's post
Carcass wrote:
Let \(\boxed {x} = 3\) , if x is an odd integer;

Let \(\boxed {x} = 6\), if x is an even integer.

\(r\) and \(s\) are integers, \(3r\) is odd, and \(5 + s\) is odd.

Quantity A
Quantity B
\(\boxed {r}\)
\(\boxed {s}\)



----ASIDE-----------------
Some important rules:
#1. ODD +/- ODD = EVEN
#2. ODD +/- EVEN = ODD
#3. EVEN +/- EVEN = EVEN

#4. (ODD)(ODD) = ODD
#5. (ODD)(EVEN) = EVEN
#6. (EVEN)(EVEN) = EVEN

-----------------------------

GIVEN:
If x is ODD, then \(\boxed {x} = 3\)
If x is EVEN, then \(\boxed {x} = 6\)

So, for example:
\(\boxed {7} = 3\)
\(\boxed {11} = 3\)
\(\boxed {3} = 3\)

And
\(\boxed {8} = 6\)
\(\boxed {22} = 6\)
\(\boxed {6} = 6\)


ALSO GIVEN:
\(3r\) is odd
Since 3 is odd and 3r is odd, we can conclude that r is ODD
This means \(\boxed {r} = 3\)


\(5 + s\) is odd
Since 5 is odd, we can conclude that s is EVEN
This means \(\boxed {s} = 6\)

We get:
Quantity A: 3
Quantity B: 6

Answer: B

Cheers,
Brent
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Re: Let x=3 , if x is an odd integer   [#permalink] 16 Aug 2019, 14:30
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