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# Let the function h be defined by h(x)= x +2. If 3h(v) = 18,

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Let the function h be defined by h(x)= x +2. If 3h(v) = 18, [#permalink]  14 May 2019, 08:32
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Let the function h be defined by $$h(x)= \sqrt{x}+2$$. If $$3h(v) = 18$$, then which one of the following is the value of $$h (\frac{v}{4})$$

(A) –4

(B) –1

(C) 0

(D) 2

(E) 4
[Reveal] Spoiler: OA

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Re: Let the function h be defined by h(x)= x +2. If 3h(v) = 18, [#permalink]  14 May 2019, 13:29
Expert's post
If provided algebra on the GRE, first look to solve algebraically. In this case using the formula: h(x)=√x+2.

Since provided the information that 3h(v) = 18 ÷ the equation by 3 to determine that h(v) = 6.

Then, replace h(v) with √v+2 = 6 and subtract 2 from each side to find that √v= 4, before squaring the equation to find that v = 16.

Finally, use that value for v to find v/4 = 4 and plug 4 into h(x)=√x+2 to find that √4+2 = 4, which matches choice E.
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Re: Let the function h be defined by h(x)= x +2. If 3h(v) = 18,   [#permalink] 14 May 2019, 13:29
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# Let the function h be defined by h(x)= x +2. If 3h(v) = 18,

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