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k is an integer such that 9(3)^3 + 4 = k

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k is an integer such that 9(3)^3 + 4 = k [#permalink] New post 07 Jun 2017, 00:54
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k is an integer such that \(9(3)^3 + 4 = k\)

Quantity A
Quantity B
The average of the
prime factors of k
16


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: k is an integer such that 9(3)^3 + 4 = k [#permalink] New post 11 Oct 2017, 07:16
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What is essential here is to notice that k is defined as a sum of two numbers so that in order to compute its prime factors, we must first find k.

Thus k = 247, then its prime factors are 17 and 19, whose mean is 17+19/2 = 16

Answer C
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Re: k is an integer such that 9(3)^3 + 4 = k [#permalink] New post 15 Nov 2017, 21:10
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What is essential here is to notice that k is defined as a sum of two numbers so that in order to compute its prime factors, we must first find k.

Thus k = 247, then its prime factors are 17 and 13, whose mean is (17+13)/2 = 16

Answer C
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Re: k is an integer such that 9(3)^3 + 4 = k [#permalink] New post 19 Feb 2018, 14:52
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First find out K=247
Then find the factor of 247.Knowing its units digit is 7 so one factor's units digit number must be 7 or 3 and 9. Since only 7 and the product of 3 and 9 give us 7 in units digit.
Use trial and error method divide 247 by 7,17,3,9,13 and 19 to find out 247 is the product of 13 and 19.
Find the average of 13 and 19 which equal to 16.Answer C.
Re: k is an integer such that 9(3)^3 + 4 = k   [#permalink] 19 Feb 2018, 14:52
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k is an integer such that 9(3)^3 + 4 = k

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