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k is an integer for which

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k is an integer for which [#permalink] New post 24 Feb 2017, 02:43
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69% (00:43) correct 30% (00:23) wrong based on 55 sessions



k is an integer for which \(\frac{1}{2^{(1-k)}} < \frac{1}{8}\)

Quantity A
Quantity B
k
-2


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: k is an integer for which [#permalink] New post 03 Mar 2017, 05:40
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Explanation

We have the expression \(\frac{1}{2^{(1 - k)}}\) and the fraction \(\frac{1}{8}\).

Rewriting \(\frac{1}{8}\) as \(\frac{1}{2^3}\).

So if 1 -k > 3 (for example 1- k = 4) then the inequality \(\frac{1}{2^{(1 - k)}} < \frac{1}{8}\).

So \(1 -k > 3\) or \(-k > 2\) or \(k <-2\).

Thus Quantity B is greater.
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Re: k is an integer for which [#permalink] New post 07 Mar 2018, 08:42
I think the explanation and the problem post have a different fraction here
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Re: k is an integer for which [#permalink] New post 07 Mar 2018, 15:48
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chgre wrote:
I think the explanation and the problem post have a different fraction here

It was a formatting error. Its fixed now.
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Re: k is an integer for which [#permalink] New post 12 Mar 2018, 01:29
B
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Re: k is an integer for which [#permalink] New post 13 Mar 2018, 16:33
correct: B
1 / 2^K-1 < 1/8
8 < 2 ^ 1-K
2^3 < 2 ^ 1-K
3 < 1-K
K < -2
so B is bigger

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Re: k is an integer for which   [#permalink] 13 Mar 2018, 16:33
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