ExplanationWe have the expression \(\frac{1}{2^{(1 - k)}}\) and the fraction \(\frac{1}{8}\).

Rewriting \(\frac{1}{8}\) as \(\frac{1}{2^3}\).

So if

1 -k > 3 (for example 1- k = 4) then the inequality \(\frac{1}{2^{(1 - k)}} < \frac{1}{8}\).

So \(1 -k > 3\) or \(-k > 2\) or \(k <-2\).

Thus Quantity B is greater.
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Sandy

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