Answer: BThe first thing that should be considered here is that these two statements are not complementary:

Probability of a side to be even: P(E)

Probability of a side to be odd: P(O)

A: P(E and E)

B: P(E and O) + P(O and E) + P(E and E) = 1 - P(O and O)

Total possible occurrences: 6*6 = 36

As P(E and O) and P(O and E) can’t be negative, seemingly B is larger than A. But let’s try:

A: P(E and E) = 9/36 = 1/4

(2 | 4 | 6, 2| 4| 6) -> (2,2), (2,4),(2,6), (4,2), …, (6,6) [9 ones]

B: P(E and O) + P(O and E) + P(E and E) = 3 * 9/36 = 3/4

P(E and O) = 9/36

(2|4|6, 1,3,5) -> 3*3 = 9

P(O and E) = 9/36

(1,3,5, 2|4|6) -> 3*3 = 9

P(E and E)= 9/36

So B is bigger than A.

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