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Joe reaches into a bag containing 5 red,

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Joe reaches into a bag containing 5 red, [#permalink] New post 20 Oct 2017, 16:07
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Question Stats:

90% (01:03) correct 9% (01:25) wrong based on 65 sessions


Joe reaches into a bag containing 5 red, 4 blue, and 8 orange jellybeans, and randomly selects three jellybeans.

Quantity A
Quantity B
The probability of selecting a red, then
a blue, then an orange jellybean
The probability of selecting a red, then
another red, then an orange jellybean


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: Joe reaches into a bag containing 5 red, [#permalink] New post 21 Oct 2017, 07:00
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I assumed that the jellybeans are extracted and then they are not put back in the bag.

Quantity A is \(\frac{5}{17}\frac{4}{16}\frac{8}{15}\), while quantity B is \(\frac{5}{17}\frac{4}{16}\frac{8}{15}\).

Answer C
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Re: Joe reaches into a bag containing 5 red, [#permalink] New post 10 Oct 2018, 21:56
Both answer is 2/51. So answer is C
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Re: Joe reaches into a bag containing 5 red, [#permalink] New post 18 Dec 2018, 08:03
5/17 * 4/16 * 8/15 hence C
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Re: Joe reaches into a bag containing 5 red, [#permalink] New post 01 Jan 2019, 15:34
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Answer: C
5 red, 4 blue and 8 orange
Selects three randomly

A: P(r and b and o) = 5/17 * 4/16 * 8/15
In first picking, there are 5 red out of 17, thus the probability of taking a red one is 5/17
In second picking, there are 16 ones remaining, out of which there are 4 blue ones, thus the probability of taking a blue one is 4/16
In third Picking, there are 15 ones remaining, out of which there are 8 orange ones, thus the probability of taking an orange one is 8/15

B: P(r and r and o) = 5/17* 4/16 * 8/15
A and ‌B are equal
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Re: Joe reaches into a bag containing 5 red,   [#permalink] 01 Jan 2019, 15:34
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Joe reaches into a bag containing 5 red,

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