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# Jill is dividing her ten-person class into two teams

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Jill is dividing her ten-person class into two teams [#permalink]  08 Jun 2019, 05:53
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Jill is dividing her ten-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?

A. 10
B. 25
C. 126
D. 252
E. 630
[Reveal] Spoiler: OA
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Re: Jill is dividing her ten-person class into two teams [#permalink]  09 Jun 2019, 10:14
Expert's post
We can divide a group of 10 people into 2 teams of 5 in $$\frac{C^5_{10}*C^5_5}{2!}=126$$ ways (dividing by 2! because the order of the groups doesn't matter).
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Re: Jill is dividing her ten-person class into two teams   [#permalink] 09 Jun 2019, 10:14
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