sandy wrote:

Total distance = 1320 miles.

Average speed is = 45 miles/hour.

Time taken for travel = \(\frac{1320}{45}=29.3333\)hours. (Quantity A)

2% of total distance = \(\frac{2}{100} \times 1320\) miles = 26.4 miles.

Time taken to travel this @ average speed = \(\frac{26.4}{45}=0.58666666666\)hours or 35.2 minutes. (Quantity B)

So numerical value of Quantity B is greater!

This is not the right answer,

The option indeed is D.

Since her average speed is given and we do not know what is her actual speed at first 2% of trip so it could be any value for example, she might have driven 60 miles per hour for the first hour and then later traveled slower than 45 miles per hour (suppose 30 m/hr)for a period of time. Because it is not known how much Janine’s speed varied on the trip, the relationship cannot be determined from the information given.

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