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Jane scored in the 68th percentile on a test, and John score [#permalink]
29 Jul 2018, 04:27
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Question Stats:
42% (00:32) correct
57% (00:51) wrong based on 126 sessions
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.
Quantity A 
Quantity B 
The proportion of the class that received a score less than John’s score 
The proportion of the class that scored equal to or greater than Jane’s score 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
22 Aug 2018, 22:42
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sandy wrote: Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.
Quantity A 
Quantity B 
The proportion of the class that received a score less than John’s score 
The proportion of the class that scored equal to or greater than Jane’s score 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given. Solution : It is not mentioned in the question whether a normal distribution or not



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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
02 Sep 2018, 23:27
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adeel wrote: sandy wrote: Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.
Quantity A 
Quantity B 
The proportion of the class that received a score less than John’s score 
The proportion of the class that scored equal to or greater than Jane’s score 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given. Solution : It is not mentioned in the question whether a normal distribution or not It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x.



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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
05 Sep 2018, 06:40
Simon wrote: adeel wrote: sandy wrote: Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.
Quantity A 
Quantity B 
The proportion of the class that received a score less than John’s score 
The proportion of the class that scored equal to or greater than Jane’s score 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given. Solution : It is not mentioned in the question whether a normal distribution or not It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x. Still do not get how both quantities are equal.



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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
05 Sep 2018, 18:12
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ExplanationAs pointed out before percentiles have nothing to do with the type of distribution.Percentiles define the proportion of a group that scores below a particular benchmark. Since John scored in the 32nd percentile, by definition, 32% of the class scored worse than John. Quantity A is equal to 32%. Jane scored in the 68th percentile, so 68% of the class scored worse than she did. Since 100 – 68 = 32, 32% of the class scored equal to or greater than Jane. Quantity B is also equal to 32%. Hence C
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
03 Jan 2020, 11:24
I do not agree with the answer because
 the first question asks "a score less than John’s score", hence less than 32, but not including 32 itself  the second asks "equal to or greater than Jane’s score", hence 10068=32, including 68th percentile itself
as a result, we need to compare "less than 32" with "exactly 32" so the answer should be B



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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
04 Jan 2020, 23:48
It is given that john scored a 32nd percentile and not 32% or 32 marks. By definition, 32 percentile means that 32% of the total test takers were below the john's score(which is not given). Similarly,10068= 32% of total test takers were either equal or above the jane's score. Hence , the quantities are equal.



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Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
06 Apr 2020, 13:41
question phrased weirdly




Re: Jane scored in the 68th percentile on a test, and John score
[#permalink]
06 Apr 2020, 13:41





