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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # Jane scored in the 68th percentile on a test, and John score  Question banks Downloads My Bookmarks Reviews Important topics
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TAGS: Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3034  , given: 394

Jane scored in the 68th percentile on a test, and John score [#permalink]
2
KUDOS
Expert's post 00:00

Question Stats: 41% (00:32) correct 58% (00:49) wrong based on 137 sessions
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

 Quantity A Quantity B The proportion of the class that received a score less than John’s score The proportion of the class that scored equal to or greater than Jane’s score

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________

Sandy
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Try our free Online GRE Test Intern Joined: 15 May 2018
Posts: 38
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Kudos [?]: 6  , given: 1

Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
3
KUDOS
sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

 Quantity A Quantity B The proportion of the class that received a score less than John’s score The proportion of the class that scored equal to or greater than Jane’s score

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Solution : It is not mentioned in the question whether a normal distribution or not Intern Joined: 17 Sep 2017
Posts: 21
Followers: 1

Kudos [?]: 15  , given: 3

Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
1
KUDOS
sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

 Quantity A Quantity B The proportion of the class that received a score less than John’s score The proportion of the class that scored equal to or greater than Jane’s score

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Solution : It is not mentioned in the question whether a normal distribution or not

It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x.
Intern Joined: 05 Sep 2018
Posts: 1
Followers: 0

Kudos [?]: 0 , given: 0

Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
Simon wrote:
sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

 Quantity A Quantity B The proportion of the class that received a score less than John’s score The proportion of the class that scored equal to or greater than Jane’s score

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Solution : It is not mentioned in the question whether a normal distribution or not

It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x.

Still do not get how both quantities are equal. Retired Moderator Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3034  , given: 394

Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
2
KUDOS
Expert's post
Explanation

As pointed out before percentiles have nothing to do with the type of distribution.

Percentiles define the proportion of a group that scores below a particular benchmark. Since John scored in the 32nd percentile, by definition, 32% of the class scored worse than John. Quantity A is equal to 32%.

Jane scored in the 68th percentile, so 68% of the class scored worse than she did. Since 100 – 68 = 32, 32% of the class scored equal to or greater than Jane. Quantity B is also equal to 32%.

Hence C
_________________

Sandy
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Intern Joined: 21 Sep 2019
Posts: 3
Followers: 0

Kudos [?]: 0 , given: 13

Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
I do not agree with the answer because

- the first question asks "a score less than John’s score", hence less than 32, but not including 32 itself
- the second asks "equal to or greater than Jane’s score", hence 100-68=32, including 68th percentile itself

as a result, we need to compare "less than 32" with "exactly 32"
so the answer should be B
Intern Joined: 31 Dec 2019
Posts: 22
Followers: 1

Kudos [?]: 15 , given: 2

Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
It is given that john scored a 32nd percentile and not 32% or 32 marks. By definition, 32 percentile means that 32% of the total test takers were below the john's score(which is not given). Similarly,100-68= 32% of total test takers were either equal or above the jane's score.
Hence , the quantities are equal.
Intern Joined: 24 Mar 2020
Posts: 34
Followers: 0

Kudos [?]: 3 , given: 4

Re: Jane scored in the 68th percentile on a test, and John score [#permalink]
question phrased weirdly Re: Jane scored in the 68th percentile on a test, and John score   [#permalink] 06 Apr 2020, 13:41
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