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Jane scored in the 68th percentile on a test, and John score

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Jane scored in the 68th percentile on a test, and John score [#permalink] New post 29 Jul 2018, 04:27
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Question Stats:

42% (00:32) correct 57% (00:51) wrong based on 126 sessions
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

Quantity A
Quantity B
The proportion of the class that received a score less than John’s score
The proportion of the class that scored equal to or greater than Jane’s score


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: Jane scored in the 68th percentile on a test, and John score [#permalink] New post 22 Aug 2018, 22:42
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sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

Quantity A
Quantity B
The proportion of the class that received a score less than John’s score
The proportion of the class that scored equal to or greater than Jane’s score


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Solution : It is not mentioned in the question whether a normal distribution or not
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink] New post 02 Sep 2018, 23:27
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adeel wrote:
sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

Quantity A
Quantity B
The proportion of the class that received a score less than John’s score
The proportion of the class that scored equal to or greater than Jane’s score


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Solution : It is not mentioned in the question whether a normal distribution or not


It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x.
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink] New post 05 Sep 2018, 06:40
Simon wrote:
adeel wrote:
sandy wrote:
Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.

Quantity A
Quantity B
The proportion of the class that received a score less than John’s score
The proportion of the class that scored equal to or greater than Jane’s score


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Solution : It is not mentioned in the question whether a normal distribution or not


It doesn't matter what distribution it is. This question tests the concept of "percentile": if x is at k percentile, then k% of the whole observations are below x.



Still do not get how both quantities are equal.
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GRE 1: Q167 V156
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Kudos [?]: 2916 [2] , given: 394

Re: Jane scored in the 68th percentile on a test, and John score [#permalink] New post 05 Sep 2018, 18:12
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Explanation


As pointed out before percentiles have nothing to do with the type of distribution.

Percentiles define the proportion of a group that scores below a particular benchmark. Since John scored in the 32nd percentile, by definition, 32% of the class scored worse than John. Quantity A is equal to 32%.

Jane scored in the 68th percentile, so 68% of the class scored worse than she did. Since 100 – 68 = 32, 32% of the class scored equal to or greater than Jane. Quantity B is also equal to 32%.

Hence C
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink] New post 03 Jan 2020, 11:24
I do not agree with the answer because

- the first question asks "a score less than John’s score", hence less than 32, but not including 32 itself
- the second asks "equal to or greater than Jane’s score", hence 100-68=32, including 68th percentile itself

as a result, we need to compare "less than 32" with "exactly 32"
so the answer should be B
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink] New post 04 Jan 2020, 23:48
It is given that john scored a 32nd percentile and not 32% or 32 marks. By definition, 32 percentile means that 32% of the total test takers were below the john's score(which is not given). Similarly,100-68= 32% of total test takers were either equal or above the jane's score.
Hence , the quantities are equal.
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Re: Jane scored in the 68th percentile on a test, and John score [#permalink] New post 06 Apr 2020, 13:41
question phrased weirdly
Re: Jane scored in the 68th percentile on a test, and John score   [#permalink] 06 Apr 2020, 13:41
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Jane scored in the 68th percentile on a test, and John score

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