It is currently 19 Apr 2019, 23:00

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Jake rides his bike for the first

Author Message
TAGS:
Founder
Joined: 18 Apr 2015
Posts: 6197
Followers: 99

Kudos [?]: 1199 [0], given: 5704

Jake rides his bike for the first [#permalink]  19 Aug 2017, 08:13
Expert's post
00:00

Question Stats:

78% (03:23) correct 21% (02:37) wrong based on 19 sessions

Jake rides his bike for the first $$\frac{2}{3}$$ of the distance from home to school, traveling at 10 miles per hour. He then walks the remaining $$\frac{1}{3}$$ of the distance at 3 miles per hour. If his total trip takes 40 minutes, how many miles is it from Jake's home to his school?

A. $$\frac{5}{4}$$

B. $$\frac{15}{4}$$

C. 5

D. 6

E. 10
[Reveal] Spoiler: OA

_________________
GRE Instructor
Joined: 10 Apr 2015
Posts: 1645
Followers: 57

Kudos [?]: 1571 [0], given: 8

Re: Jake rides his bike for the first [#permalink]  28 Aug 2017, 15:00
Expert's post
Carcass wrote:
Jake rides his bike for the first $$\frac{2}{3}$$ of the distance from home to school, traveling at 10 miles per hour. He then walks the remaining $$\frac{1}{3}$$ of the distance at 3 miles per hour. If his total trip takes 40 minutes, how many miles is it from Jake's home to his school?

A. $$\frac{5}{4}$$

B. $$\frac{15}{4}$$

C. 5

D. 6

E. 10

(time spent on bike) + (time spent walking) = 2/3 hours (= 40 minutes)

Let D = total distance (in miles) from home to school
So, Jake rode his bike for a distance of (2/3)D miles, which equals 2D/3 miles
Then Jake walked for a distance of (1/3)D miles, which equals D/3 miles

Time = distance/rate

So, we can write: (2D/3)/10 + (D/3)/3 = 2/3
Multiply both sides by 30 to get: 6D/3 + 10D/3 = 60/3
Multiply both sides by 3 to get: 6D + 10D = 60
Simplify: 16D = 60
Solve: D = 60/16 = 30/8 = 15/4

[Reveal] Spoiler:
B

RELATED VIDEO FROM OUR COURSE
_________________

Brent Hanneson – Creator of greenlighttestprep.com

Re: Jake rides his bike for the first   [#permalink] 28 Aug 2017, 15:00
Display posts from previous: Sort by