wongpcla wrote:

simon1994 wrote:

Here we can set up the following equation with both Areas:

1) Triangle: (a^2)/2 = A

2) Sqaure: b^2 = A

A stands for Area, a for side of triangle and b for side of square.

If we solve these equations for the sides a and b respectively, we obtain the following

1) a^2 = 2A

2) b^2 = A

Now we can set up perimeter equations with the comparable variable A

1) 2A * 3 => 6A

2) A*4 => 4A

Hence the perimeter of the triangle(6A) is bigger than that of the square(4A) Therefore A>B

Would you explain why you put "2A * 3" and "A*4"

you times their area, this is also okay to compare their sides?

thank you !

Hi,

I changed by previous answer their was a slight mistake. However the reasoning remains the same.

Regarding your question: We need to obtain compare the Perimeter of a triangle with the perimeter of a square.

So we we have to multiply by 3 to obtain the perimeter of a triangle and by 4 to obtain the perimeter of a square.

Hope that helped!