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# In year X, 1of the agency's refugee housing expenditures,

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In year X, 1of the agency's refugee housing expenditures, [#permalink]  24 Aug 2018, 11:09
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Question Stats:

70% (02:12) correct 29% (03:03) wrong based on 41 sessions
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In year X, $$\frac{1}{3}$$ of the agency's refugee housing expenditures, $$\frac{1}{5}$$ of its emergency workers expenditures, $$\frac{1}{4}$$ of its commodities expenditures, and $$\frac{2}{3}$$ of its post-disaster assistance expenditures were directly related to one earthquake. The total of these expenditures was approximately how many millions of dollars?

(A) 5

(B) 7

(C) 9

(D) 11

(E) 13
[Reveal] Spoiler: OA

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Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Kudos [?]: 1312 [1] , given: 251

Re: In year X, 1of the agency's refugee housing expenditures, [#permalink]  28 Aug 2018, 04:42
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Carcass wrote:
Attachment:
income.jpg

In year X, $$\frac{1}{3}$$ of the agency's refugee housing expenditures, $$\frac{1}{5}$$ of its emergency workers expenditures, $$\frac{1}{4}$$ of its commodities expenditures, and $$\frac{2}{3}$$ of its post-disaster assistance expenditures were directly related to one earthquake. The total of these expenditures was approximately how many millions of dollars?

(A) 5

(B) 7

(C) 9

(D) 11

(E) 13

For easy calculation lets take the value as integer

1. $$\frac{1}{3}$$ of refugee housing expenditures = $$\frac{1}{3} * (12)$$= 4%

2. $$\frac{1}{5}$$ emergency workers expenditures = $$\frac{1}{5} * (20)$$= 4%

3. $$\frac{1}{4}$$ of its commodities expenditures = $$\frac{1}{4} * (20)$$ = 5%

4. $$\frac{2}{3}$$ of its post-disaster assistance expenditures = $$\frac{2}{3} * (12)$$= 8%

Therefore total expenditure = $$4 + 4 + 5 + 8 = 21$$% = i.e. $$(0.21 * 60)$$ million = 12.6 million nearly equals to 13 million
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Re: In year X, 1of the agency's refugee housing expenditures,   [#permalink] 28 Aug 2018, 04:42
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