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In year X, 1of the agency's refugee housing expenditures,

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In year X, 1of the agency's refugee housing expenditures, [#permalink] New post 24 Aug 2018, 11:09
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Question Stats:

53% (02:20) correct 46% (02:46) wrong based on 13 sessions
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In year X, \(\frac{1}{3}\) of the agency's refugee housing expenditures, \(\frac{1}{5}\) of its emergency workers expenditures, \(\frac{1}{4}\) of its commodities expenditures, and \(\frac{2}{3}\) of its post-disaster assistance expenditures were directly related to one earthquake. The total of these expenditures was approximately how many millions of dollars?

(A) 5

(B) 7

(C) 9

(D) 11

(E) 13
[Reveal] Spoiler: OA

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Re: In year X, 1of the agency's refugee housing expenditures, [#permalink] New post 28 Aug 2018, 04:42
Carcass wrote:
Attachment:
income.jpg


In year X, \(\frac{1}{3}\) of the agency's refugee housing expenditures, \(\frac{1}{5}\) of its emergency workers expenditures, \(\frac{1}{4}\) of its commodities expenditures, and \(\frac{2}{3}\) of its post-disaster assistance expenditures were directly related to one earthquake. The total of these expenditures was approximately how many millions of dollars?

(A) 5

(B) 7

(C) 9

(D) 11

(E) 13


For easy calculation lets take the value as integer

1. \(\frac{1}{3}\) of refugee housing expenditures = \(\frac{1}{3} * (0.12 * 60)\)= 3.6 million

2. \(\frac{1}{5}\) emergency workers expenditures = \(\frac{1}{5} * (0.2 * 60)\)= 2.4 million

3. \(\frac{1}{4}\) of its commodities expenditures = \(\frac{1}{4} * (0.2 * 60)\) = 3 million

4. \(\frac{2}{3}\) of its post-disaster assistance expenditures = \(\frac{2}{5} * (0.13 * 60)\)= 5.2 million

Therefore total expenditure = \(3.6 + 2.4 + 3 + 5.2 = 14.2\) = nearly equals to 13 million i.e. option E
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Re: In year X, 1of the agency's refugee housing expenditures,   [#permalink] 28 Aug 2018, 04:42
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In year X, 1of the agency's refugee housing expenditures,

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