Carcass wrote:

In the xy-plane, what is the slope of the line whose equation is 3x - 2y = 8 ?

A) -4

B)\(-\frac{8}{3}\)

C) \(\frac{2}{3}\)

D) \(\frac{3}{2}\)

E) 2

I'd typically use Sandy's approach of rewriting the equation in slope y-intercept form.

That said, an alternate approach is to find two points ON the line and then find the slope between those two points.

GIVEN: 3x - 2y = 8

If x = 0, we get: 3(0) - 2y = 8

Solve for y to get y = -4

So, the point

(0, -4) lies on the line.

Find a second point on the line.

GIVEN: 3x - 2y = 8

If x = 2, we get: 3(2) - 2y = 8

Solve for y to get y = -1

So, the point

(2, -1) lies on the line.

Now use the

slope formula to find the slope between

(0, -4) and

(2, -1)Slope = [(-4) - (-1)]/(0 - 2)

= (-3)/(-2)

= 3/2

Answer: D

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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