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In the xy-plane, find the following. (a) Slope and y-intercep

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In the xy-plane, find the following. (a) Slope and y-intercep [#permalink] New post 24 May 2019, 08:13
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In the xy-plane, find the following.

(a) Slope and y-intercept of the line with equation 2y+x=6

(b) Equation of the line passing through the point (3,2) with y-intercept 1

(c) The y-intercept of a line with slope 3 that passes through the point (−2,1)

(d) The x-intercepts of the graphs in (a), (b), and (c)

[Reveal] Spoiler: OA
(a) Slope: \(- \frac{1}{2}\); y-intercept:; 3 (b) \(y=\frac{x}{3}+1\) (c) 7 (d) \(6,-3, - \frac{7}{3}\)



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Re: In the xy-plane, find the following. (a) Slope and y-intercep [#permalink] New post 27 May 2019, 13:09
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Carcass wrote:
In the xy-plane, find the following.

(a) Slope and y-intercept of the line with equation 2y+x=6

(b) Equation of the line passing through the point (3,2) with y-intercept 1

(c) The y-intercept of a line with slope 3 that passes through the point (−2,1)

(d) The x-intercepts of the graphs in (a), (b), and (c)

[Reveal] Spoiler: OA
(a) Slope: \(- \frac{1}{2}\); y-intercept:; 3 (b) \(y=\frac{x}{3}+1\) (c) 7 (d) \(6,-3, - \frac{7}{3}\)




It's often useful to take the equation of a line and rewrite it slope y-intercept form y = mx + b, where m is the line's slope, and b is the line's y-intercept.

(a) Slope and y-intercept of the line with equation \(2y + x = 6\)

Take: \(2y + x = 6\)

Subtract x from both sides: \(2y = -x + 6\)

Divide both sides by 2 to get: \(y = -\frac{1}{2}x + 3\)

We can see that the slope is \(-\frac{1}{2}\), and the y-intercept is 3
----------------------------------

(b) Equation of the line passing through the point (3,2) with y-intercept 1

If the y-intercept is 1, then \(b = 1\)

So, far we have: \(y = mx + 1\)

Since the point (3,2) lies ON the line, it's coordinates (x = 3 and y = 2) must SATISFY the equation of the line.

Replace values to get: \(2 = m(3) + 1\)

Subtract 1 from both sides to get: \(1 = 3m\)

Solve: \(m = \frac{1}{3}\)

The equation of the line is \(y = \frac{1}{3}x + 1\)
----------------------------------

(c) The y-intercept of a line with slope 3 that passes through the point (−2,1)

If the slope is 3, then \(m = 3\)

So, far we have: \(y = 3x + b\)

Since the point (−2,1) lies ON the line, it's coordinates (x = -2 and y = 1) must SATISFY the equation of the line.

Replace values to get: \(1 = 3(-2) + b\)

Simplify: \(1 = -6 + b\)

Solve: \(b = 7\)

So, the y-intercept is 7

By the way, the equation of the line is \(y = 3x + 7\)
----------------------------------

(d) The x-intercepts of the graphs in (a), (b), and (c)
Key concept: the x-intercept is the x-value when y = 0

So, for each equation, replace y with 0 and solve for x.

a) Replace y with 0 to get: \(0 = -\frac{1}{2}x + 3\)

Subtract 3 from both sides: \(-3 = -\frac{1}{2}x\)

Solve: \(x = 6\)

The x-intercept is 6


b) Replace y with 0 to get: \(0 = \frac{1}{3}x + 1\)

Subtract 1 from both sides: \(-1 = \frac{1}{3}x\)

Solve: \(x = -3\)

The x-intercept is -3



c) Replace y with 0 to get: \(0 = 3x + 7\)

Subtract 7 from both sides: \(-7 = 3x\)

Solve: \(x = -\frac{7}{3}\)

The x-intercept is \(-\frac{7}{3}\)

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Re: In the xy-plane, find the following. (a) Slope and y-intercep   [#permalink] 27 May 2019, 13:09
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In the xy-plane, find the following. (a) Slope and y-intercep

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