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In the xyplane, a circle is centered at the point (4,3) a [#permalink]
21 Dec 2017, 16:57
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In the xyplane, a circle is centered at the point (4,3) and passes through the origin. What is the area of the circle? A. 9π B. 12π C. 16π D. 20π E. 25π kudo for the right solution and explanation
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Re: In the xyplane, a circle is centered at the point (4,3) a [#permalink]
22 Dec 2017, 02:41
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We can calculate the distrance from the point to the origin Squroo (0  (4) + (03) Squroot 4^2 + 3^2 Squroot 16 + 9 Squroot 25 Or 5 distance is 5 So the radius muss be 5 since it says that the origine lied on the circle. Aera of circle is r^2*pi So we have 25*pi so answer is E



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Re: In the xyplane, a circle is centered at the point (4,3) a [#permalink]
22 Dec 2017, 06:39
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Popo wrote: We can calculate the distrance from the point to the origin Squroo (0  (4) + (03) Squroot 4^2 + 3^2 Squroot 16 + 9 Squroot 25 Or 5 distance is 5 So the radius muss be 5 since it says that the origine lied on the circle. Aera of circle is r^2*pi So we have 25*pi so answer is E Hi could you plz read before posting. Always check the spelling and mathematical expression https://greprepclub.com/forum/rulesfor ... 1083.html
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Re: In the xyplane, a circle is centered at the point (4,3) a [#permalink]
22 Dec 2017, 06:48
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Carcass wrote: In the xyplane, a circle is centered at the point (4,3) and passes through the origin. What is the area of the circle?
A. 9π B. 12π C. 16π D. 20π E. 25π
kudo for the right solution and explanation Here, Since the coordinates for the centre of the circle = (4,3) and it passes through the orgin i.e co ordinates are =(0,0) NOw the distance from (4,3) to point (0,0) will give the radius of the circle Distance between two points (x1,y1) and (x2,y2) in the xy plane = \(\sqrt{{(x2  x1)^2 + (y2  y1)^2}}\) Therefore the distance between (4,3) and (0,0) = \(\sqrt{{(0  (4))^2 + (0  3)^2}}\) =\(\sqrt{25}\) = 5 SInce Area of the circle = \(\pi * (radius)^2\) = \(\pi * 5^2\) =\(25\pi\) i. e option E
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Re: In the xyplane, a circle is centered at the point (4,3) a [#permalink]
16 May 2018, 09:21
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Carcass wrote: In the xyplane, a circle is centered at the point (4,3) and passes through the origin. What is the area of the circle?
A. 9π B. 12π C. 16π D. 20π E. 25π Since the circle is centered at the point (4,3) and passes through the origin, we see that the radius is the hypotenuse of a triangle, with sides of 3 and 4, so we have a 345 right triangle with a hypotenuse of 5, which means the radius of the circle is also 5. Thus, the area of the circle is π(5^2) = 25π, Answer: E
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Re: In the xyplane, a circle is centered at the point (4,3) a
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