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In the xy-coordinate system, the distance between points (2\

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In the xy-coordinate system, the distance between points (2\ [#permalink]  11 Jul 2018, 03:12
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82% (00:53) correct 17% (00:49) wrong based on 23 sessions
In the xy-coordinate system, the distance between points $$(2\sqrt{3}, - \sqrt{2})$$ and $$(5\sqrt{3}, 3\sqrt{2})$$ is approximately

A 4.1
B 5.9
C 6.4
D 7.7
E 8.1
[Reveal] Spoiler: OA
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Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Re: In the xy-coordinate system, the distance between points (2\ [#permalink]  11 Jul 2018, 11:05
amorphous wrote:
In the xy-coordinate system, the distance between points $$(2\sqrt{3}, - \sqrt{2})$$ and $$(5\sqrt{3}, 3\sqrt{2})$$ is approximately

A 4.1
B 5.9
C 6.4
D 7.7
E 8.1

The distance between two points in xy co-ordinates : $$\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$$

So here the distance between two points = $$\sqrt {(5\sqrt{3} - 2\sqrt{3})^2 + (3\sqrt{2} + \sqrt{3})^2} = \sqrt {(3\sqrt{3})^2 + (4\sqrt{2})^2} = \sqrt {27 + 32} = \sqrt{59} = 7.7$$

$$\sqrt{59}$$= nearly equals to 7.7

since $$\sqrt{64} = 8$$and $$\sqrt{49} = 7$$

so $$\sqrt{59}$$should be between 7 and 8, so only option D satisfy
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Joined: 27 Oct 2018
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Re: In the xy-coordinate system, the distance between points (2\ [#permalink]  02 Nov 2018, 10:18
Difficulty level hard?
:/
Re: In the xy-coordinate system, the distance between points (2\   [#permalink] 02 Nov 2018, 10:18
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