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In the xy-coordinate system, the distance between points (2\ [#permalink]
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Question Stats: 68% (00:53) correct 31% (01:53) wrong based on 19 sessions
In the xy-coordinate system, the distance between points $$(2\sqrt{3}, -\sqrt{2}) and (5\sqrt{3}, 3\sqrt{2}$$) is approximately

A 4.1
B 5.9
C 6.4
D 7.7
E 8.1
[Reveal] Spoiler: OA VP Joined: 20 Apr 2016
Posts: 1302
WE: Engineering (Energy and Utilities)
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Re: In the xy-coordinate system, the distance between points (2\ [#permalink]
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amorphous wrote:
In the xy-coordinate system, the distance between points $$(2\sqrt{3}, -\sqrt{2}) and (5\sqrt{3}, 3\sqrt{2}$$) is approximately

A 4.1
B 5.9
C 6.4
D 7.7
E 8.1

Here we can use the formula:- $$\sqrt{(y2 -y1)^2 + (x2 -x1)^2}$$

Here y2= $$5\sqrt{3}$$; y1 = $$2\sqrt{3}$$

x2 = $$3\sqrt{2}$$ and x1 = $$\sqrt{2}$$

So putting the values in the formula we have:

= $$\sqrt{(5\sqrt{3}-2\sqrt{3})^2+(3\sqrt{2}+\sqrt{2})^2}$$=$$\sqrt{(3\sqrt{3})^2+(4\sqrt{2})^2}$$ = $$\sqrt{59}$$

Now we know $$7^2$$=49 and $$8^2$$=64, so 59 should in between $$7<\sqrt{59}<8$$.

Therefore only D. gives a possible value
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GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests Re: In the xy-coordinate system, the distance between points (2\   [#permalink] 27 Jun 2018, 00:34
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