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In the xy-coordinate system, the distance between points (2\

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In the xy-coordinate system, the distance between points (2\ [#permalink] New post 26 Jun 2018, 21:26
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68% (00:53) correct 31% (01:53) wrong based on 19 sessions
In the xy-coordinate system, the distance between points \((2\sqrt{3}, -\sqrt{2}) and (5\sqrt{3}, 3\sqrt{2}\)) is approximately

A 4.1
B 5.9
C 6.4
D 7.7
E 8.1
[Reveal] Spoiler: OA
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Re: In the xy-coordinate system, the distance between points (2\ [#permalink] New post 27 Jun 2018, 00:34
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amorphous wrote:
In the xy-coordinate system, the distance between points \((2\sqrt{3}, -\sqrt{2}) and (5\sqrt{3}, 3\sqrt{2}\)) is approximately

A 4.1
B 5.9
C 6.4
D 7.7
E 8.1



Here we can use the formula:- \(\sqrt{(y2 -y1)^2 + (x2 -x1)^2}\)

Here y2= \(5\sqrt{3}\); y1 = \(2\sqrt{3}\)

x2 = \(3\sqrt{2}\) and x1 = \(\sqrt{2}\)

So putting the values in the formula we have:

= \(\sqrt{(5\sqrt{3}-2\sqrt{3})^2+(3\sqrt{2}+\sqrt{2})^2}\)=\(\sqrt{(3\sqrt{3})^2+(4\sqrt{2})^2}\) = \(\sqrt{59}\)

Now we know \(7^2\)=49 and \(8^2\)=64, so 59 should in between \(7<\sqrt{59}<8\).

Therefore only D. gives a possible value
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Re: In the xy-coordinate system, the distance between points (2\   [#permalink] 27 Jun 2018, 00:34
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In the xy-coordinate system, the distance between points (2\

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