GreenlightTestPrep wrote:

Line J: 4x - 7 = 6y

Line K: 6y + 3x = -2

Line L: 2x = 5 - y

In the x-y coordinate plane, lines J, K and L are defined by the above equations.

Point B is the point of intersection of lines J and K. Point C is the point of intersection of lines K and L.

What is the slope of line segment BC?

A) -3/2

B) -2/3

C) -1/2

D) 1/2

E) 2/3

Key Concepts: point B lies on line K, and point C lies on line K

Since both points lie on line K, the slope between points B and C will be the same as the slope of line K.

To find the slope of line K, let's take the equation of line K (6y + 3x = -2), and rewrite it in slope y-intercept form (y = mx + b)

Take: 6y + 3x = -2

Subtract 3x from both sides to get: 6y = -3x - 2

Divide both sides by 6 to get: y = (-3/6)x - 2/6

Simplify to get: y = (-1/2)x - 1/3

So, line K has a slope of -1/2 and a y-intercept of -1/3

Answer: C

Cheers,

Brent

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Brent Hanneson – Creator of greenlighttestprep.com

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