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# In the standard xy-coordinate plane, the xy-pairs (0, 2) and

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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 141
Followers: 1

Kudos [?]: 43 [0], given: 59

In the standard xy-coordinate plane, the xy-pairs (0, 2) and [#permalink]  25 Mar 2020, 02:04
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Question Stats:

99% (02:23) correct 0% (00:00) wrong based on 7 sessions
In the standard xy-coordinate plane, the xy-pairs (0, 2) and (2, 0) define a line, and the xy-pairs (-2, -1) and (2, 1) define another line. At which of the following points do the two lines intersect?

(A) $$[\frac{4}{3}, \frac{2}{3}]$$

(B) $$[\frac{3}{2}, \frac{4}{3}]$$

(C) $$[-\frac{1}{2}, \frac{3}{2}]$$

(D) $$[\frac{3}{4}, -\frac{2}{3}]$$

(E) $$[-\frac{3}{4}, -\frac{2}{3}]$$
[Reveal] Spoiler: OA
Intern
Joined: 24 Mar 2020
Posts: 34
Followers: 0

Kudos [?]: 3 [1] , given: 4

Re: In the standard xy-coordinate plane, the xy-pairs (0, 2) and [#permalink]  25 Mar 2020, 03:06
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KUDOS
I don't know if it is the best methods, but it surely gets you to the right answer. First, you find the slope of both lines with the formula y2-y1/x2-x1. Then you find the Y-intercept of both lines. Finally, you have two equations in this format y = ax + b and you put them equal and find x = 4/3 then you plug x into one of the two-equation and find y = 2/3
Re: In the standard xy-coordinate plane, the xy-pairs (0, 2) and   [#permalink] 25 Mar 2020, 03:06
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