It is currently 27 Sep 2020, 02:02

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# In the rectangular solid above, TU=3

Author Message
TAGS:
Retired Moderator
Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 171

Kudos [?]: 2923 [0], given: 394

In the rectangular solid above, TU=3 [#permalink]  01 Dec 2015, 18:40
Expert's post
00:00

Question Stats:

92% (00:44) correct 7% (01:06) wrong based on 85 sessions
Attachment:

#GREpracticequestion In the rectangular solid above, TU=3, UV=4.jpg [ 6.75 KiB | Viewed 3382 times ]

In the rectangular solid above, TU=3, UV=4, and VR=2. What is the area of the shaded rectangular region?

[Reveal] Spoiler: OA
10

Practice Questions
Question: 12
Page: 150
Difficulty: easy

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

Retired Moderator
Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 171

Kudos [?]: 2923 [0], given: 394

Re: In the rectangular solid above, TU=3 [#permalink]  01 Dec 2015, 18:44
Expert's post
Solution

Here we have in the rectangle RSTV the side RS = 2 and VT is the hypotenuse of the right triangle VTU where TU = 3 and UV = 4.

By Pythagoras theorem for right triangle we know that

VT = $$\sqrt{3^2 + 4^2}$$ =5

So the Area of the shaded region = $$2 * 5$$= 10.
_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

GRE Instructor
Joined: 10 Apr 2015
Posts: 3838
Followers: 148

Kudos [?]: 4496 [2] , given: 69

Re: In the rectangular solid above, TU=3 [#permalink]  08 Jun 2019, 16:26
2
KUDOS
Expert's post
sandy wrote:
Attachment:
The attachment #GREpracticequestion In the rectangular solid above, TU=3, UV=4.jpg is no longer available

In the rectangular solid above, TU=3, UV=4, and VR=2. What is the area of the shaded rectangular region?

Notice that that we have a right triangle in the diagram.
Attachment:

In the rectangular solid above, TU=3, UV=4, and VR=21.png [ 28.99 KiB | Viewed 2899 times ]

You might recognize that 3 and 4 are part of the Pythagorean Triplet 3-4-5, in which case the missing side has length 5

Alternatively, we can apply the Pythagorean Theorem.
If we let x = the length of the hypotenuse of the triangle, we can write: 3² + 4² = x²
Simplify: 9 + 16 = x²
Simplify: 25 = x²
Solve: [b]x = 5[/b]
Attachment:

In the rectangular solid above, TU=3, UV=4, and VR=22.png [ 29.62 KiB | Viewed 2899 times ]

At this point, we should see that the shaded rectangular region has dimensions 2 by 5
Attachment:

In the rectangular solid above, TU=3, UV=4, and VR=23.png [ 29.72 KiB | Viewed 2899 times ]

Area of rectangle = (base)(height)
= (2)(5)
= 10

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
If you enjoy my solutions, you'll like my GRE prep course.

Re: In the rectangular solid above, TU=3   [#permalink] 08 Jun 2019, 16:26
Display posts from previous: Sort by