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TAGS: Founder  Joined: 18 Apr 2015
Posts: 6866
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In the rectangular coordinate system, (x,y) is a point on a [#permalink]
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Expert's post 00:00

Question Stats: 19% (00:33) correct 80% (00:53) wrong based on 26 sessions
In the rectangular coordinate system, (x,y) is a point on a circle that has center (3,2) and is tangent to the x-axis at (3,0).

 Quantity A Quantity B The least possible value of x zero

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation
[Reveal] Spoiler: OA

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Last edited by Carcass on 13 Sep 2018, 09:24, edited 1 time in total.
Edited the OA
Manager Joined: 25 Nov 2017
Posts: 51
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Kudos [?]: 43 , given: 5

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
For this one, since the radius is 3 it supposed to touch the x intercept 0?
Founder  Joined: 18 Apr 2015
Posts: 6866
Followers: 114

Kudos [?]: 1326 , given: 6284

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
Expert's post

Regards
_________________ Director Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Kudos [?]: 666  , given: 147

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
1
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Carcass wrote:
In the rectangular coordinate system, (x,y) is a point on a circle that has center (3,2) and is tangent to the x-axis at (3,0).

 Quantity A Quantity B The least possible value of x zero

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation

Here the distance between the centre of the circle (3,2) to the point (3,0),tangent to x asis is = $$\sqrt{(3-3)^2 + (0-2)^2}$$ = 2, which is the radius of the circle.

Now (x,y) is any point in this circle with radius 2, so the minimum value of x > 0

Hence option A
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Intern Joined: 12 Nov 2018
Posts: 25
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Kudos [?]: 7 , given: 16

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
the least possible value of x is 1 as the radius is 2. So while touching (1,2 ) point , x will be the least possible value Supreme Moderator
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Posts: 370
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Kudos [?]: 111  , given: 4

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
1
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Expert's post
Carcass wrote:
In the rectangular coordinate system, (x,y) is a point on a circle that has center (3,2) and is tangent to the x-axis at (3,0).

 Quantity A Quantity B The least possible value of x zero

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation

Now the distance between points (3,2) and (3,0) will be the radius, so radius = 2, which is the change in y axis when x remains 3.

We are looking for the least possible value of x will be the distance between center and radius 2. Thus 3-2=1
But B is 0.

Hence A is greater.

A
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