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# In the rectangular coordinate system, (x,y) is a point on a

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In the rectangular coordinate system, (x,y) is a point on a [#permalink]  20 Dec 2017, 15:35
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9% (00:02) correct 90% (00:46) wrong based on 21 sessions
In the rectangular coordinate system, (x,y) is a point on a circle that has center (3,2) and is tangent to the x-axis at (3,0).

 Quantity A Quantity B The least possible value of x zero

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation
[Reveal] Spoiler: OA

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Last edited by Carcass on 13 Sep 2018, 09:24, edited 1 time in total.
Edited the OA
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Kudos [?]: 41 [0], given: 5

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]  20 Dec 2017, 18:09
For this one, since the radius is 3 it supposed to touch the x intercept 0?
Moderator
Joined: 18 Apr 2015
Posts: 5532
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Kudos [?]: 1113 [0], given: 5130

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]  21 Dec 2017, 16:33
Expert's post

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Kudos [?]: 582 [1] , given: 113

Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]  22 Dec 2017, 23:27
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Carcass wrote:
In the rectangular coordinate system, (x,y) is a point on a circle that has center (3,2) and is tangent to the x-axis at (3,0).

 Quantity A Quantity B The least possible value of x zero

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation

Here the distance between the centre of the circle (3,2) to the point (3,0),tangent to x asis is = $$\sqrt{(3-3)^2 + (0-2)^2}$$ = 2, which is the radius of the circle.

Now (x,y) is any point in this circle with radius 2, so the minimum value of x > 0

Hence option A
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Re: In the rectangular coordinate system, (x,y) is a point on a   [#permalink] 22 Dec 2017, 23:27
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