Nov 15 10:00 PM PST  11:00 PM PST Economist GRE Tutor’s plans all come with a set of practice exams that mirror the official GRE test. Our academic team worked hard to make sure that the practice tests are the closest experience you can get to the real GRE exam. Nov 16 10:00 PM PST  11:00 PM PST Within each of the 16 learning modules (Geometry, Statistics, Sentence Equivalence, etc.) that comprise the course, you'll find plenty of free videos to help you make an informed purchase. I also have 4 modules in which all of the videos are free. Nov 18 08:00 PM PST  09:00 PM PST Working with an Online GRE Tutor is Convenient and Effective Nov 22 08:00 PM PST  11:00 PM PST Magoosh is excited to offer you a free GRE practice test with video answers and explanations. If you’re thinking about taking the GRE or want to see how effective your GRE test prep has been, pinpoint your strengths and weaknesses with this quiz!
Author 
Message 
TAGS:


Founder
Joined: 18 Apr 2015
Posts: 8733
Followers: 175
Kudos [?]:
2030
[1]
, given: 8060

In the first half of last year, a team won 60 percent of the [#permalink]
05 Mar 2017, 09:11
1
This post received KUDOS
Question Stats:
51% (01:45) correct
48% (01:30) wrong based on 98 sessions
In the first half of last year, a team won 60 percent of the games it played. In the second half of last year, the team played 20 games, winning 3 of them. If the team won 50 percent of the games it played last year, what was the total number of games the team played last year? A) 60 B) 70 C) 80 D) 90 E) 100
_________________
Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests.




Retired Moderator
Joined: 07 Jun 2014
Posts: 4808
WE: Business Development (Energy and Utilities)
Followers: 145
Kudos [?]:
2273
[6]
, given: 393

Re: In the first half of last year, a team won 60 percent of the [#permalink]
11 Mar 2017, 20:13
6
This post received KUDOS
ExplanationTotal games last year = \(x\) Games in 2nd half of year = \(20\) Games in 1st half of year = \(x  20\) 60% of games in first half + 3 games in second half = 50% of the total games\(0.60 \times (x  20) + 3 = 0.50 \times x\) \(0.60(x  20) + 3 = 0.50x\) \(0.60x  12 + 3 = 0.50x\) \(0.60x  9 = 0.50x\) \(9 = 0.10x\) \(x =90\) Hence option D is correct.
_________________
Sandy If you found this post useful, please let me know by pressing the Kudos Button
Try our free Online GRE Test



Intern
Joined: 20 Dec 2017
Posts: 30
Followers: 0
Kudos [?]:
17
[0], given: 9

Re: In the first half of last year, a team won 60 percent of the [#permalink]
17 Feb 2018, 04:17
Please could you correct me since there is possibility that I can make this mistake again …
I did the following X = number of total games in the first half of the year 0.6x+3=0.5(x+20) 0.6x+3=0.5x+10 0.1x=7 X=70, which is not correct



Retired Moderator
Joined: 07 Jun 2014
Posts: 4808
WE: Business Development (Energy and Utilities)
Followers: 145
Kudos [?]:
2273
[0], given: 393

Re: In the first half of last year, a team won 60 percent of the [#permalink]
17 Feb 2018, 12:35
yell2012prime Array[WROTE]: Please could you correct me since there is possibility that I can make this mistake again …
I did the following X = number of total games in the first half of the year 0.6x+3=0.5(x+20) 0.6x+3=0.5x+10 0.1x=7 X=70, which is not correct X=70 is correct!. Now add the 20 to get toatal games.
_________________
Sandy If you found this post useful, please let me know by pressing the Kudos Button
Try our free Online GRE Test



Intern
Joined: 17 Feb 2018
Posts: 9
Followers: 0
Kudos [?]:
2
[0], given: 2

Re: In the first half of last year, a team won 60 percent of the [#permalink]
17 Feb 2018, 16:15
sandy Array[WROTE]: yell2012prime Array[WROTE]: Please could you correct me since there is possibility that I can make this mistake again …
I did the following X = number of total games in the first half of the year 0.6x+3=0.5(x+20) 0.6x+3=0.5x+10 0.1x=7 X=70, which is not correct X=70 is correct!. Now add the 20 to get toatal games. trial and error made me take something like 2.5 minutes to answer this question... guess that's too long, yikes



Intern
Joined: 20 Dec 2017
Posts: 30
Followers: 0
Kudos [?]:
17
[1]
, given: 9

Re: In the first half of last year, a team won 60 percent of the [#permalink]
17 Feb 2018, 17:03
1
This post received KUDOS
sandy Array[WROTE]: yell2012prime Array[WROTE]: Please could you correct me since there is possibility that I can make this mistake again …
I did the following X = number of total games in the first half of the year 0.6x+3=0.5(x+20) 0.6x+3=0.5x+10 0.1x=7 X=70, which is not correct X=70 is correct!. Now add the 20 to get toatal games. Thank you, this is why I have to REread prompt again and don't rush



Intern
Joined: 20 Dec 2017
Posts: 30
Followers: 0
Kudos [?]:
17
[0], given: 9

Re: In the first half of last year, a team won 60 percent of the [#permalink]
17 Feb 2018, 17:10
matayo Array[WROTE]: sandy Array[WROTE]: yell2012prime Array[WROTE]: Please could you correct me since there is possibility that I can make this mistake again …
I did the following X = number of total games in the first half of the year 0.6x+3=0.5(x+20) 0.6x+3=0.5x+10 0.1x=7 X=70, which is not correct X=70 is correct!. Now add the 20 to get toatal games. trial and error made me take something like 2.5 minutes to answer this question... guess that's too long, yikes If you solve 20 such quest you can do it in 30 sec (after 3rd one), but we should be more careful with final answer bc there is possibility to make careless mistake (like I did when I took full cat)



Manager
Joined: 15 Feb 2018
Posts: 53
Followers: 1
Kudos [?]:
19
[0], given: 33

Re: In the first half of last year, a team won 60 percent of the [#permalink]
23 Feb 2018, 00:11
Brilliant technique! sandy Array[WROTE]: Explanation
Total games last year = \(x\)
Games in 2nd half of year = \(20\)
Games in 1st half of year = \(x  20\)
60% of games in first half + 3 games in second half = 50% of the total games
\(0.60 \times (x  20) + 3 = 0.50 \times x\)
\(0.60(x  20) + 3 = 0.50x\)
\(0.60x  12 + 3 = 0.50x\)
\(0.60x  9 = 0.50x\)
\(9 = 0.10x\)
\(x =90\)
Hence option D is correct.



Target Test Prep Representative
Status: Head GRE Instructor
Affiliations: Target Test Prep
Joined: 09 May 2016
Posts: 161
Location: United States
Followers: 7
Kudos [?]:
170
[1]
, given: 0

Re: In the first half of last year, a team won 60 percent of the [#permalink]
05 Jul 2018, 15:56
1
This post received KUDOS
Carcass Array[WROTE]: In the first half of last year, a team won 60 percent of the games it played. In the second half of last year, the team played 20 games, winning 3 of them. If the team won 50 percent of the games it played last year, what was the total number of games the team played last year? A) 60 B) 70 C) 80 D) 90 E) 100 We can n = the number of games played in the first half. Thus, we see that 0.6n is the number of games won in the first half of the year and (0.6n + 3) is the total number of games won for the entire year. We also see that (n + 20) is the total number of games played during the entire year Thus, we can create the equation: (0.6n + 3)/(n + 20) = 1/2 2(0.6n + 3) = n + 20 1.2n + 6 = n + 20 0.2n = 14 n = 70 Therefore, they played a total of 70 + 20 = 90 games last year. Answer: D
_________________
5star rated online GRE quant self study course See why Target Test Prep is the top rated GRE quant course on GRE Prep Club. Read Our Reviews



GRE Instructor
Joined: 10 Apr 2015
Posts: 2554
Followers: 91
Kudos [?]:
2718
[2]
, given: 40

Re: In the first half of last year, a team won 60 percent of the [#permalink]
21 Sep 2018, 05:46
2
This post received KUDOS
Carcass Array[WROTE]: In the first half of last year, a team won 60 percent of the games it played. In the second half of last year, the team played 20 games, winning 3 of them. If the team won 50 percent of the games it played last year, what was the total number of games the team played last year? A) 60 B) 70 C) 80 D) 90 E) 100 Let T = TOTAL number of games played last yearThe team won 50 percent of the games it played last yearSo, TOTAL NUMBER OF WINS = 0.5TIn the SECOND HALF of last year, the team played 20 games, winning 3 of themNumber of WINS IN SECOND HALF = 3If the team plays 20 games in the SECOND HALF, then T  20 = the number of games played in the FIRST HALF In the first half of last year, a team won 60 percent of the games it played. So, the team won 60% of the T  20 games it played in the FIRST HALF Number of WINS IN FIRST HALF = (0.6)(T  20)We know that: WINS IN FIRST HALF + WINS IN SECOND HALF = TOTAL NUMBER OF WINSSo: (0.6)(T  20) + 3 = 0.5TExpand: 0.6T  12 + 3 = 0.5T Simplify left side: 0.6T  9 = 0.5T Subtract 0.6T from both sides to get: 9 = 0.1T Solve: T = 90 Answer: D Cheers, Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Day emails



Intern
Joined: 23 Sep 2018
Posts: 6
Followers: 0
Kudos [?]:
5
[0], given: 0

Re: In the first half of last year, a team won 60 percent of the [#permalink]
01 Oct 2018, 03:22
let x be total number of games played let y be total number of games won 1st half / games played =x / games won 0.6x 2nd half / games played = 20 / games won 3 total games won = 0.5x  total games played 20+x = ? (plug in the equation below) total games won 0.6x +3 = 0.5x 0.6x +3 = 0.5(20+x) x = 70 hence 20+70 = 90 i made it every time when I need help with multiple choice questions or other assignments I use [url="https://assignmentmasters.org/"]"https://assignmentmasters.org/"[/url]



Manager
Joined: 08 Dec 2018
Posts: 94
Followers: 0
Kudos [?]:
37
[1]
, given: 30

Re: In the first half of last year, a team won 60 percent of the [#permalink]
21 May 2019, 06:24
1
This post received KUDOS
yell2012prime Array[WROTE]: Please could you correct me since there is possibility that I can make this mistake again …
I did the following X = number of total games in the first half of the year 0.6x+3=0.5(x+20) 0.6x+3=0.5x+10 0.1x=7 X=70, which is not correct Please look at your (X+20) . this is your total game, NOT X only. So, you are correct if you calculate X+20=> 70+20=> 90 I guess, here lies the tricks of the math. If we take Sandy's way, then we will not fall into the GRE trap!




Re: In the first half of last year, a team won 60 percent of the
[#permalink]
21 May 2019, 06:24





