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# In the figure shown, J, K, and L are the centers of the thre

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In the figure shown, J, K, and L are the centers of the thre [#permalink]  29 Jul 2020, 10:39
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100% (03:33) correct 0% (00:00) wrong based on 6 sessions
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GRE In the figure shown, J, K, and L are the centers of the thre.jpg [ 32.38 KiB | Viewed 96 times ]

In the figure shown, J, K, and L are the centers of the three circles. The radius of the circle with center J is four times the radius of the circle with center L, and the radius of the circle with center J is two times the radius of the circle with center K. If the sum of the areas of the three circles is $$525\pi$$ square units, what is the measure, in units, of JL?

A. 35

B. 45

C. 50

D. 65

E. 70

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[Reveal] Spoiler: OA

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Re: In the figure shown, J, K, and L are the centers of the thre [#permalink]  29 Jul 2020, 10:45
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Let the radius of the circle with center L be x.
=> the radius of the circle with center K = 2x
and, the radius of the circle with center J = 4x

Now, the sum of the areas of the three circles is 525π
=> π*x*x + π*(2x)*(2x) + π*(4x)*(4x) = 525*π
=> x^2 + 4*x^2 + 16*x^2 = 525
=> 21*x^2 = 525
=> x^2 = 21
=> x = 5
=> JL = 5 + 10 + 10 + 20 = 45

Re: In the figure shown, J, K, and L are the centers of the thre   [#permalink] 29 Jul 2020, 10:45
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