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# In the figure, if ∠A = ∠C, then x =

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In the figure, if ∠A = ∠C, then x = [#permalink]  12 Mar 2019, 10:33
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Question Stats:

100% (01:24) correct 0% (00:00) wrong based on 11 sessions
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#GREpracticequestion In the figure, if.jpg [ 32.83 KiB | Viewed 1725 times ]

In the figure, if $$∠A = ∠C$$, then $$x =$$

(A) 30

(B) 60

(C) 90

(D) 150

(E) 180
[Reveal] Spoiler: OA

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Re: In the figure, if ∠A = ∠C, then x = [#permalink]  13 Mar 2019, 08:54
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Carcass wrote:
Attachment:
#GREpracticequestion In the figure, if.jpg

In the figure, if $$∠A = ∠C$$, then $$x =$$

(A) 30

(B) 60

(C) 90

(D) 150

(E) 180

Since ∠A = ∠C, we k know that ∠C = y°/2.
Add this information to the diagram...

Since angles in a triangle add to 180°...

... we can write: y°/2 + y°/2 + x° = 180°
Simplify to get: y° + x° = 180°

Since OPPOSITE angles are EQUAL,...

... we know that y° = x°

We can now take y° + x° = 180° and replace y° with x° to get: x° + x° = 180°
Simplify: 2x° = 180°
Solve: x = 90

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Re: In the figure, if ∠A = ∠C, then x = [#permalink]  08 Sep 2019, 00:31
90
Re: In the figure, if ∠A = ∠C, then x =   [#permalink] 08 Sep 2019, 00:31
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