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In the figure below, vertex Q of square OPQR is on a circle [#permalink]
Expert's post 00:00

Question Stats: 58% (00:32) correct 41% (00:33) wrong based on 17 sessions
In the figure below, vertex Q of square OPQR is on a circle with center O. If the area of the square is 8, what is the area of the circle?

Attachment: #GREpracticequestion In the figure below, vertex Q of square OPQR.png [ 10.4 KiB | Viewed 1614 times ]

A) $$8 \pi$$

B) $$8\pi \sqrt{2}$$

C) $$16 \pi$$

D) $$32 \pi$$

E) $$64 \pi$$
[Reveal] Spoiler: OA

_________________ Intern Joined: 26 Mar 2017
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Re: In the figure below, vertex Q of square OPQR is on a circle [#permalink]
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Area of the square = 8, so side =√8 = 2√2.

Diagonal of the square = s√2
= 2√2 * 2 = 4

Diagonal of the square = radius of the circle

Area of the circle = 16π

Answer - C Re: In the figure below, vertex Q of square OPQR is on a circle   [#permalink] 02 Feb 2019, 09:58
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