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In the figure below, vertex Q of square OPQR is on a circle

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In the figure below, vertex Q of square OPQR is on a circle [#permalink] New post 02 Feb 2019, 09:09
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In the figure below, vertex Q of square OPQR is on a circle with center O. If the area of the square is 8, what is the area of the circle?

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#GREpracticequestion In the figure below, vertex Q of square OPQR.png
#GREpracticequestion In the figure below, vertex Q of square OPQR.png [ 10.4 KiB | Viewed 603 times ]


A) \(8 \pi\)

B) \(8\pi \sqrt{2}\)

C) \(16 \pi\)

D) \(32 \pi\)

E) \(64 \pi\)
[Reveal] Spoiler: OA

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Re: In the figure below, vertex Q of square OPQR is on a circle [#permalink] New post 02 Feb 2019, 09:58
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Area of the square = 8, so side =√8 = 2√2.

Diagonal of the square = s√2
= 2√2 * 2 = 4

Diagonal of the square = radius of the circle

Area of the circle = 16π

Answer - C
Re: In the figure below, vertex Q of square OPQR is on a circle   [#permalink] 02 Feb 2019, 09:58
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In the figure below, vertex Q of square OPQR is on a circle

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