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# In the figure below, vertex Q of square OPQR is on a circle

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Joined: 18 Apr 2015
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Kudos [?]: 1115 [0], given: 5134

In the figure below, vertex Q of square OPQR is on a circle [#permalink]  02 Feb 2019, 09:09
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Question Stats:

66% (00:21) correct 33% (00:51) wrong based on 6 sessions
In the figure below, vertex Q of square OPQR is on a circle with center O. If the area of the square is 8, what is the area of the circle?

Attachment:

#GREpracticequestion In the figure below, vertex Q of square OPQR.png [ 10.4 KiB | Viewed 209 times ]

A) $$8 \pi$$

B) $$8\pi \sqrt{2}$$

C) $$16 \pi$$

D) $$32 \pi$$

E) $$64 \pi$$
[Reveal] Spoiler: OA

_________________
Intern
Joined: 26 Mar 2017
Posts: 23
WE: Account Management (Internet and New Media)
Followers: 0

Kudos [?]: 12 [1] , given: 53

Re: In the figure below, vertex Q of square OPQR is on a circle [#permalink]  02 Feb 2019, 09:58
1
KUDOS
Area of the square = 8, so side =√8 = 2√2.

Diagonal of the square = s√2
= 2√2 * 2 = 4

Diagonal of the square = radius of the circle

Area of the circle = 16π

Re: In the figure below, vertex Q of square OPQR is on a circle   [#permalink] 02 Feb 2019, 09:58
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